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Use algebra.

Let x=number of broken eggs. Since there are six times as many unbroken as broken, 6x=number of unbroken eggs.

number of broken eggs (x) plus number of unbroken eggs (6x) equals 21

x + 6x = 21

7x = 21 (combine like terms)

x = 3 (divide both sides of equation by 7)

Since x=number of broken eggs, 3 eggs are broken.

Since 6x=number of unbroken eggs, 6*3=18 for 18 unbroken eggs.

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