To find the resistance of the light bulb, you can use Ohm's Law, which states that ( V = I \times R ). First, determine the total voltage from the 4 D-cell batteries; each D-cell typically provides about 1.5 volts, so the total voltage is ( 4 \times 1.5 = 6 ) volts. Given the current ( I ) is 2 amps, you can rearrange the formula to find resistance ( R ): ( R = V / I = 6 , \text{volts} / 2 , \text{amps} = 3 , \text{ohms} ). Thus, the resistance of the light bulb is 3 ohms.