Yes. Sodium will react vigorously with water. The reaction is very exothermic and may even cause fire. 2Na + 2H2O ---> 2NaOH + H2
Potassium reacts violently with water to form POTASSIUM HYDROXIDE(KOH)and hydrogen gas K+H2O---------- KOH+H2 The H2 catches fire due to the heat of the reaction which in turn ignites potassium .potassium burn's with a crimson flame.
One big difference: Hydrogen are an extremely explosive gas molecules (H2), while water is a fire extinguishing fluid (H2O).
The role of hydrogen gas, H2, in the formation of a water molecule, H2O is rather simple. It reacts with 1/2 mole of oxygen to form the water: H2 + 1/2 O2 → H2O or 2 H2 + O2 → 2 H2O Each hydrogen in the hydrogen gas is oxidized from (0) to (+1) and is reducing the oxygen from (0) to (-II) in oxidation state.
A magnisium fire burns at a significantly higher temperature than a typical fire with other combustable materials. If a water extinguisher were to be used on a metal fire, the heat of the fire will cause the water to break down into its chemical constituants Hydrogen, and Oxygen (H2O), and instead of removing heat from the fire it will actually cause the fire to intensify due to the addition of fuel Hydrogen (H2) and an oxidizer Oxygen (O). Other extinguishers can extinguish the fire, but again due to the extreme heat it will take significantly more agent to extinguish this type of fire than would be needed for a standard combustables fire. An extinguishing agent which is designed for use on a metal fire can withstand the extreme heat and will extinguish the fire by blanketing the burning metal and smothering the fire by depriving it of oxygen. Dry Sand for example would work well. There are other agents which could be used on this type of fire which extinguish the fire interfering with the fire's chemical reaction rather than smothering it.
H2 + o = H2o
it's H2 O
It is a chemical change (reaction) because the chemical composition of the products (O2 and H2) is different from the chemical composition of the water (H2O).
There is, just not (nearly) enough to explode with the oxygen present.
2 Li(s) + 2H2O(l) = 2LiOH(aq) +H2(g) the lithium hydroxide is aqueous because it is in solution.
When 1.24 L of H2 gas reacts with O2 at STP, the mole ratio between H2 and H2O is 2:2. This means that for every 1 mole of H2 gas reacting, 1 mole of water is formed. Using the ideal gas law, you can calculate the number of moles of H2 gas reacting, and then use the mole ratio to determine the number of moles of water formed. Finally, you can convert moles of water to grams using the molar mass of water.
Water gas is a mixture of CO and H2 and H2O. Over oxide catalysts the "water gas shift" reaction occurs that removes the CO by reacting it with water to produce CO2 and more H2. CO + H2O -> CO2 + H2