After extensive research, I can find no credible article which cites that Jay-Z is of Haitian decent.
Jayz became 40 years old on Decemmber 4th 2009
real roots= Overdamped equal roots= critically damped complex roots /imaginary roots = Underdamped
There is no difference between real solutions and real roots.
The real fourth roots are -0.3 and 0.3
There will be 2 real roots
Quadratics can two, one or no real roots.
If you have a quadratic function with real coefficients then it can have: two distinct real roots, or a real double root (two coincidental roots), or no real roots. In the last case, it has two complex roots which are conjugates of one another.
No.
They can be either. If they are roots of a real polynomial then purely imaginary would be symmetric and only real roots can be skew symmetric.
The short answer is "Nothing". In the complex domain, the number of nth roots of any real number is n. Every non-negative real number has 2 square roots. Every real number has 3 cube roots. Every non-negative real number has 2 real square roots and 2 imaginary ones. and so on. So what?
Yes. A cubic equation can have 3 real roots. Depending on their size, each of three intervals could contain a root. In that case different intervals must give different roots.Yes. A cubic equation can have 3 real roots. Depending on their size, each of three intervals could contain a root. In that case different intervals must give different roots.Yes. A cubic equation can have 3 real roots. Depending on their size, each of three intervals could contain a root. In that case different intervals must give different roots.Yes. A cubic equation can have 3 real roots. Depending on their size, each of three intervals could contain a root. In that case different intervals must give different roots.
There are two roots, both real: -13 and +13