21os in a g
( S(s) + O_2(g) → SO_2(g) ) ( 2S(s) + 3O_2(g) → 2SO_3(g) )
In sulfur dioxide (SO2), the molar mass of sulfur (S) is 32.07 g/mol, and for oxygen (O) it is 16.00 g/mol. Therefore, the molar mass of SO2 is 32.07 g/mol (S) + 2 * 16.00 g/mol (O) = 64.07 g/mol. If you know the mass of the sample, you can calculate the number of moles of sulfur and oxygen using their respective molar ratios in SO2.
it is a combustion. the word equation would be: sulfur + oxygen → sulfur dioxide the balanced chemical equation: S(s) + O₂(g) → SO₂(g)
The ratio of oxygen to copper oxide is 2.0 g O / 10 g CuO = 0.2 g O / g CuO. Therefore, in a 30 g sample of the compound, the mass of oxygen would be 0.2 g O/g CuO * 30 g CuO = 6.0 g of oxygen.
The first step is to convert the masses of Fe and O into moles: 174.86 g Fe is 3.13 moles of Fe, and 75.14 g O is 4.69 moles of O. The ratio of Fe to O in the compound is approximately 2:3. Therefore, the empirical formula of the compound is Fe2O3, which is iron(III) oxide (also known as rust).
here is its s s s * - S P ( - P O [%P] P O s Y i 4 - s s s s s s s * S P ( - P O [%P] P P s O [4o] i - * * * * ( ( ( ( % % % % 4 4 4 4 - s s s s * - S P ( - P O [%P] P O P P s O [4o] i - s s s s s * - S P ( - O O s P O O s P O O g g g g g * - s D ( - D D [%D] D D S - [4s] s s s s s s s s* - S P ( - O O s P O O s P O O - O g g g D g D ( - P s S - [%D] D D s D s 4 - i o O - g g g D g D ( - P s S S D s D D s D s 4 i o O - g g g D g h ( H h - D D D D S S s - s s s s * - S P ( - O P O o o s o O 4Share this:
O. G. S. Crawford was born on 1886-10-28.
O. G. S. Crawford died on 1957-11-28.
O G S. Crawford has written: 'The eye goddess'
YESSSS!!!!! SHE IS ABSOLUTELY G-E-O-R-G-E-O-U-S!!!!!!!! YESSSS!!!!! SHE IS ABSOLUTELY G-E-O-R-G-E-O-U-S!!!!!!!!
CSI Miami - 2002 G-O- 9-21 is rated/received certificates of: Netherlands:12
21 spots on a dice
G. S. Maddala was born on 1933-05-21.
88.5%
21 gays in your swimming pool
21 shillings in a Guinea
21 notes on the great scale