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S in (SO4)-2 has a charge of +6, in SO2 S has a charge of +4. To go from +6 to +4 you must gain two electrons. The (SO4)-2 is reduced (reduction is gaining electrons). Therefore it reduces the 2br-, so (SO4)-2 is the reducing agent

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Q: 2br- plus so4-2 plus 4h plus -------br2 plus so2 plus 2h2o in this reaction what is the oxidising agent?
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