The reaction between ammonia and boron trifluoride, BF3
If you have recently read the page on covalent bonding, you may remember boron trifluoride as a compound which doesn't have a noble gas structure around the boron atom. The boron only has 3 pairs of electrons in its bonding level, whereas there would be room for 4 pairs. BF3 is described as being electron deficient.
The lone pair on the nitrogen of an ammonia molecule can be used to overcome that deficiency, and a compound is formed involving a co-ordinate bond.
Using lines to represent the bonds, this could be drawn more simply as:
The second diagram shows another way that you might find co-ordinate bonds drawn. The nitrogen end of the bond has become positive because the electron pair has moved away from the nitrogen towards the boron - which has therefore become negative. We shan't use this method again - it's more confusing than just using an arrow.
The chemical formula for bromine trifluoride is BrF3.
The balanced chemical equation for the decomposition of nitrogen trifluoride (NF3) is 2NF3 → N2 + 3F2. This reaction involves breaking down NF3 into nitrogen gas (N2) and fluorine gas (F2) through decomposition.
Decomposition equation:2 NF3 ----> N2 + 3 F2
The balanced chemical equation would be: NF3 + F2 -> N + 3F2 The coefficient for fluorine would be 2 and the symbol is F2.
B + 3F [arrow] BF3 Boron and fluorine yield boron (III) fluoride.
The chemical formula for bromine trifluoride is BrF3.
The chemical equation is:2 NF3--------- ----------------->N2 + 3 F2
The chemical formula is PF3. The reaction with phsphorus is 2P + 3F2 -> 2PF3
2NF3 --> N2 + 3F2
The balanced chemical equation for the decomposition of nitrogen trifluoride (NF3) is 2NF3 → N2 + 3F2. This reaction involves breaking down NF3 into nitrogen gas (N2) and fluorine gas (F2) through decomposition.
N2 + 3f2 >> 2nf3 ( I see they are messing up the capitalizations again. Those second N and F are capitalized )
The chemical equation is:2 NF3 + 3 H2 = N2 + 6 HF
Decomposition equation:2 NF3 ----> N2 + 3 F2
The balanced chemical equation would be: NF3 + F2 -> N + 3F2 The coefficient for fluorine would be 2 and the symbol is F2.
B + 3F [arrow] BF3 Boron and fluorine yield boron (III) fluoride.
A chemical equation is a shorthand description of a chemical reaction.
A chemical reaction can be represented by a chemical equation.