two chlorine atoms
Barium, with an atomic number of 56, needs to lose 2 electrons to achieve a stable electron configuration, similar to a noble gas. This is because barium will then have a filled outer electron shell, following the octet rule.
Barium forms an ion with a 2+ charge because it has 2 valence electrons in its outer shell. By losing these 2 electrons, barium achieves a stable electron configuration similar to a noble gas, which is energetically favorable.
Na+ is the formula of the ion formed when sodium achieves a stable electron configuration.
What symbol would represent a chlorine ion that has ionized to have a stable electron configuration?
The noble gas configuration for fermium (Fm) is [Rn] 5f12 7s2. It represents the electron configuration of fermium in a stable state, where it mimics the electron arrangement of the noble gas radon (Rn) to achieve a more stable configuration.
In forming the molecule HF, the fluorine (F) atom attains the electron configuration of a stable octet by sharing one electron with hydrogen (H) to form a single covalent bond. This results in fluorine having a full outer shell with a total of eight electrons, achieving a stable electron configuration.
if lithium loses one electron it attains the stable noble gas electron configuration of helium. hence it is highly reactive.
Sodium loses an electron to achieve a stable electron configuration like the nearest noble gas, which is neon. By losing one electron, sodium attains a full outer shell and becomes more stable with a positive 1 charge.
Barium, with an atomic number of 56, needs to lose 2 electrons to achieve a stable electron configuration, similar to a noble gas. This is because barium will then have a filled outer electron shell, following the octet rule.
The element that gains 1 electron to attain the noble gas configuration of Xenon (Xe) is iodine (I). When iodine gains an electron, it achieves a stable electron configuration with a filled outer shell, similar to that of Xenon.
When barium becomes an ion, it typically loses two electrons to achieve a stable electron configuration, resulting in a barium ion with a charge of +2. This ion is represented as Ba²⁺. The loss of these two electrons allows barium to attain the same electron configuration as the nearest noble gas, xenon.
Barium has 2 electrons in its outermost shell. To achieve a noble gas electron configuration similar to xenon, which has 8 electrons in its outermost shell, barium would need to give up 2 electrons. This would leave barium with a full outer shell and a stable electron configuration.
Potassium (K) needs to lose one electron to become stable, as it belongs to group 1 in the periodic table and has one electron in its outer shell. By losing this electron, potassium achieves a full outer shell and attains a stable electron configuration.
Barium forms an ion with a 2+ charge because it has 2 valence electrons in its outer shell. By losing these 2 electrons, barium achieves a stable electron configuration similar to a noble gas, which is energetically favorable.
Barium loses two electrons in a reaction, so it becomes positive or a cation.
Na+ is the formula of the ion formed when sodium achieves a stable electron configuration.
The element with the noble-gas configuration Ne 3s2 is sodium (Na). Sodium has an electron configuration of 1s2 2s2 2p6 3s1, but when it loses one electron, it attains the stable electron configuration of neon by having 2 electrons in the 3s orbital.