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A gas has a volume of 2.8L at a temp of 27 celsius What temp Celsius is needed to expand the volume to 15L?
Wiki User
∙ 8y ago
First, you start by listing all of your givens; this will help you know what you have, and what you need to find.
V1 = 2.8 L
T1 = 25 C + 273 = 300 K. The temperature always has to be in kelvin; so, if you degree Celsius, you have to convert it to kelvin by using the equation K= degrees Celsius + 273
V2 = 15L
T2 = ?
V1/T1 = V2/T2 By looking at our given, we know you have to use this equation.
2.8L/300K = 15L/T2 We have to cross-multiply. (Basic Algebra)
T2 2.8L/2.8L = 4500KL/2.8L
T2 = 1607 K
1607 K = 1334 C
Wiki User
∙ 8y ago
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