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The question seems to be a nice tidy exercise all ready for someone to jump in and

go to work on it. Unfortunately, however, "kw" is not a unit of energy, so the question

is completely unbounded, and loaded with wiggle-room.

Let's see what we can do with it:

One widely-quoted value for the specific heat of water is " 4.187 kJ / kg K ", meaning

4,187 joules to change the temperature of 1 kg of water 1 Kelvin (or 1° C).

-- To make it easy on ourselves, we assume without proof or discussion that

the mass of our 1.45L of water is 1.45 kg.

-- So it takes (4,187 x 1.45) = 6,071 joules to accomplish each °C that we want to

raise its temperature.

That's about all we can do with the information given in the question, because

it doesn't give us any defined amount of energy.

If, instead of "94 kilowatts", we use "94 kilowatt-seconds", THEN we would have

94,000 joules. If the water were to absorb every single erg of that and settle into

thermal equilibrium, its temperature would rise by

94,000 / 6,071 = 15.48° C

and its final temperature would be 40.48° C.

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