2AlBr3 + 3Cl2 -> 2AlCl3 + 3Br2
The chemical equation for this reaction is: 2 AlBr3 + 3 Cl2 -> 2 AlCl3 + 3 Br2 It is a redox reaction where aluminum bromide is oxidized to aluminum chloride and chlorine is reduced to bromine.
The chemical formula for lithium oxide is Li2O, for chlorine gas it is Cl2, for aluminum it is Al, and for bromide it is Br. Therefore, the formulas you provided are: lithium oxide - Li2O, chlorine gas - Cl2, aluminum - Al, and bromide - Br.
The balanced chemical equation for this reaction is: 2AlBr3 + 3Cl2 -> 2AlCl3 + 3Br2.
AlBr3 is the formula for aluminum (III) bromide.
This is a redox reaction, specifically a double displacement reaction where aluminum bromide and chlorine gas react to form aluminum chloride and bromine gas. In this reaction, aluminum undergoes a change in oxidation state, from +3 to 0, while chlorine goes from 0 to -1.
Yes. Chlorine is more reactive than bromine.
Aluminum bromide (AlBr3) + Chlorine (Cl2) → Aluminum chloride (AlCl3) + Bromine (Br2)
The chemical equation for this reaction is: 2 AlBr3 + 3 Cl2 -> 2 AlCl3 + 3 Br2 It is a redox reaction where aluminum bromide is oxidized to aluminum chloride and chlorine is reduced to bromine.
The chemical equation is:2 AlBr3 + 3 Cl2 = 2 AlCl3 + 3 Br2
The reaction between aluminum bromide and chlorine gas to form aluminum chloride and bromine gas is a redox reaction, specifically a single displacement reaction. In this reaction, aluminum undergoes oxidation by losing electrons to chlorine to form aluminum chloride, while chlorine is reduced by gaining electrons from aluminum bromide to form bromine gas.
The chemical equation is:2 AlBr3 + 3 Cl2 = 2 AlCl3 + 3 Br2
The chemical equation is:2 AlBr3 + 3 Cl2 = 2 AlCl3 + 3 Br2
The chemical formula for lithium oxide is Li2O, for chlorine gas it is Cl2, for aluminum it is Al, and for bromide it is Br. Therefore, the formulas you provided are: lithium oxide - Li2O, chlorine gas - Cl2, aluminum - Al, and bromide - Br.
The balanced chemical equation for this reaction is: 2AlBr3 + 3Cl2 -> 2AlCl3 + 3Br2.
AlBr3 is the formula for aluminum (III) bromide.
This is a redox reaction, specifically a double displacement reaction where aluminum bromide and chlorine gas react to form aluminum chloride and bromine gas. In this reaction, aluminum undergoes a change in oxidation state, from +3 to 0, while chlorine goes from 0 to -1.
The colour of aluminum bromide is white.