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What is bauxite used to produce?
aluminium
What is the word equation for fluorine and potassium?
Fluorine and potassium react violently with one another to produce potassium fluoride and emit copious heat.
When 4 moles of aluminum are allowed to react with an excess of chlorine gas Cl2 how many moles of aluminum chloride are produced?
When 4 moles of aluminum react with an excess of chlorine gas, 4 moles of aluminum chloride are produced. This is because the balanced chemical equation for the reaction is: 2Al + 3Cl2 -> 2AlCl3 This means that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride, so 4 moles of aluminum will produce 4 moles of aluminum chloride.
What flame color does aluminum nitrate produce?
Aluminum nitrate does not produce a specific flame color when burned. The flame color produced by a compound is typically due to the metal ion present, rather than the nitrate anion. Aluminum itself does not produce a significant color in flames.
Reaction between ammonium nitrate and aluminum chloride the newly formed aluminum compound will be?
The reaction between ammonium nitrate and aluminum chloride will not produce a new aluminum compound. Instead, it will lead to the formation of ammonium chloride and aluminum nitrate as products.
How do the elements magnesium and fluorine produce the compound magnesium fluoride is by what?
Magnesium and fluorine will produce magnesium fluoride by ionic bonding.
Metallic aluminum can be obtained by electrolysis of aluminum fluoride dissolved in molten k3alf6. what mass of aluminum is obtained at the cathode if a 5 ampere current is applied for 4 hours?
Also How many grams and what volume of fluorine (@ STP) could be liberated at the anode? Also How many hours would the electrolysis need to continue to produce 75g of aluminum with a current of 15 amperes?
What is bauxite used to produce?
aluminium
How many grams of aluminum is required to produce 25.0 grams of aluminum sulfate?
To find the amount of aluminum needed to produce aluminum sulfate, you need to consider the molar mass of aluminum sulfate and the ratio of aluminum in the compound. First, calculate the molar mass of aluminum sulfate (Al2(SO4)3). Then, find the ratio of aluminum in the compound (2 moles of Al in 1 mole of Al2(SO4)3). Finally, use this information to calculate the grams of aluminum needed to produce 25.0 grams of aluminum sulfate.
What is the word equation for fluorine and potassium?
Fluorine and potassium react violently with one another to produce potassium fluoride and emit copious heat.
What is the formula equation of hydrogen reacts with fluorine to produce hydrogen fluoride?
The balanced chemical equation for the reaction of hydrogen with fluorine to produce hydrogen fluoride is: 2H2 + F2 → 4HF
What is the balanced equation for aluminum reacting with iron II oxide to produce aluminum oxide and iron?
The balanced equation for aluminum reacting with iron(II) oxide to produce aluminum oxide and iron is: 2Al + FeO -> Al2O3 + 2Fe.
How is cast aluminum produced?
Casting is a fairly simple and inexpensive way to produce aluminum. Casting occurs when molten (very hot) aluminum is poured into a mold to produce a desired shape or pattern.
What element should fluorine replace in lithium bromide?
Fluorine will replace bromine to produce the compound lithium fluoride in a single replacement reaction.
Is aluminum more reactive with hydrochloric acid or sodium hydroxide?
aluminum will produce tiny bubbles
What is the rock used to make aluminum?
The rock used to make aluminum is called bauxite. Bauxite is a sedimentary rock that is the primary source of aluminum. It is mined and processed to extract aluminum oxide, which is then used to produce aluminum metal.
What is the theoretical yield of aluminum oxide if 3.20 mol of aluminum metal is exposed to 2.70 mol of oxygen?
The balanced chemical equation for the formation of aluminum oxide is: 4Al + 3O2 -> 2Al2O3. This means that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Using the given moles of aluminum and oxygen, we can determine the limiting reactant and the theoretical yield of aluminum oxide. In this case, the oxygen is the limiting reactant, which means it will run out first. Therefore, all of the 2.70 mol of oxygen will react with aluminum to produce aluminum oxide. Since the ratio of aluminum to aluminum oxide is 4:2, the 2.70 mol of oxygen will react with (2/3)*2.70 mol of aluminum to produce aluminum oxide, which is approximately 1.80 mol.
