3 Ca(OH)2 + 2 H3PO4 --> Ca3(PO4)2 +6 H2O
Note:
Ca(OH)2 is not very soluble in water but enough to react with the acid, but may be some excess will be needed
The equation for the reaction between phosphoric acid (H3PO4) and ammonium hydroxide (NH4OH) is: H3PO4 + NH4OH -> (NH4)3PO4 + H2O This balanced equation shows the chemical reaction where phosphoric acid reacts with ammonium hydroxide to form ammonium phosphate and water.
The reaction between iron(III) hydroxide (Fe(OH)3) and phosphoric acid (H3PO4) will result in the formation of iron(III) phosphate (FePO4) and water (H2O). The balanced chemical equation for this reaction is: Fe(OH)3 + 3H3PO4 → FePO4 + 3H2O
We know that sodium hydroxide (NaOH) is a base and that phosphoric acid (H3PO4) is an acid. The balanced equation for the reaction is: 3NaOH + H3PO4 -----> Na3PO4 + 3H2O Remember that all bases react with acids in what is called an acid-base reaction. The result is the formation of a salt and water. Try working out other reactions like this yourself.
The balanced chemical equation for the reaction between calcium hydroxide and phosphoric acid is: 3Ca(OH)2 + 2H3PO4 -> Ca3(PO4)2 + 6H2O Using the mole ratio from the balanced equation, we find that 1 mole of calcium hydroxide reacts with 2/3 mole of calcium phosphate. First, calculate the number of moles of calcium hydroxide: 21.5g / 74.093g/mol = 0.290 moles Then, use the mole ratio to find the moles of calcium phosphate that can be produced: 0.290 moles * (1 mole Ca3(PO4)2 / 3 moles Ca(OH)2) = 0.097 moles Lastly, convert moles of calcium phosphate to grams: 0.097 moles * 310.176g/mol = 30 grams of calcium phosphate could be recovered.
The balanced chemical equation for this reaction is: 3H3PO4 + 6Ca(OH)2 -> 2Ca3(PO4)2 + 6H2O This balanced equation ensures that there is conservation of mass for each element present in the reaction.
To find the amount of sodium hydroxide needed to react with 150g of phosphoric acid, you first need to determine the balanced chemical equation between sodium hydroxide and phosphoric acid. From there, you can use stoichiometry to calculate the amount of sodium hydroxide needed.
The equation for the reaction between phosphoric acid (H3PO4) and ammonium hydroxide (NH4OH) is: H3PO4 + NH4OH -> (NH4)3PO4 + H2O This balanced equation shows the chemical reaction where phosphoric acid reacts with ammonium hydroxide to form ammonium phosphate and water.
Phosphoric acid plus calcium hydroxide will react to form calcium phosphate and water. The balanced chemical equation for this reaction is: 3H3PO4 + Ca(OH)2 -> Ca3(PO4)2 + 6H2O.
Calcium phosphate is produced when phosphoric acid reacts with calcium hydroxide. This is a chemical reaction that forms a solid salt precipitate.
KOH for potassium hydroxide, and H3PO4 for phosphoric acid.
Phosphoric acid (H3PO4) is a weak acid, while sodium hydroxide (NaOH) is a strong base. When mixed, they undergo a neutralization reaction to form water and sodium phosphate (Na3PO4). The balanced chemical equation for this reaction is H3PO4 + 3NaOH → Na3PO4 + 3H2O.
The reaction between iron(III) hydroxide (Fe(OH)3) and phosphoric acid (H3PO4) will result in the formation of iron(III) phosphate (FePO4) and water (H2O). The balanced chemical equation for this reaction is: Fe(OH)3 + 3H3PO4 → FePO4 + 3H2O
You can get DAP (Di-Ammonium Phosphate) or Map (Mono-Ammonium phosphate), depending on how they were reacted.
Yes, when mercury II hydroxide and phosphoric acid react, they undergo a neutralization reaction to form mercury II phosphate and water. The balanced chemical equation for the reaction is: Hg(OH)2 + 2H3PO4 → Hg3(PO4)2 + 4H2O.
You can calculate the concentration of a phosphoric acid solution by determining the volume of sodium hydroxide needed to neutralize it in a titration. The molarity of the sodium hydroxide solution and the balanced chemical equation for the reaction will allow you to find the moles of phosphoric acid present, hence the concentration.
The chemical equation for phosphoric acid is H3PO4.
The balanced chemical equation for the reaction between cesium hydroxide solution (CsOH) and phosphoric acid (H3PO4) is: 3 CsOH + H3PO4 → Cs3PO4 + 3 H2O This equation is balanced because there is an equal number of atoms of each element on both sides of the equation.