S8 + 8o2 --> 8so2
First, balance the chemical equation: S8 + 8 O2 -> 8 SO2. Calculate the moles of each reactant using their molar masses. The limiting reactant is the one that produces the least amount of SO2, which is S8 in this case. Therefore, use the stoichiometry of the balanced equation to calculate the mass of SO2 produced from 31.5g of S8.
S8 + 8 O2 → 8 SO2 burning sulfur in the presence of oxygen
S8 + 12O2 = 8SO3.Since there are 8 sulfur on the left, you must have 8 on the right, so 8SO3. Now you have 24 oxygen on the right, so you need 24 on the left. Multiplying O2 by 12 balances it.
To balance the chemical equation ZnS + O2 = ZnO + SO2, you need to make sure that the number of each type of atom is the same on both sides of the equation. Start by adding coefficients to the compounds; in this case, a coefficient of 2 in front of ZnS and SO2 balances the equation: 2 ZnS + 3 O2 = 2 ZnO + 2 SO2.
The chemical symbol of sulfur in equations is S. However, the real chemical formula is S8, so basically 8 atoms of sulfur react to become one molecule. S8 has a crown shape with three spikes on top and two spikes on the bottom. It is too much a bother to write S8 and balance it so we write S in equations.
First, balance the chemical equation: S8 + 8 O2 -> 8 SO2. Calculate the moles of each reactant using their molar masses. The limiting reactant is the one that produces the least amount of SO2, which is S8 in this case. Therefore, use the stoichiometry of the balanced equation to calculate the mass of SO2 produced from 31.5g of S8.
Sulfur is generally S8. S8 + 8 O2 → 8 SO2
The molar mass of S8 is 256 g/mol. To find the maximum mass of S8 produced, calculate the number of moles of each reactant (4 moles for SO2 and 1 mole for H2S). Then, determine which reactant limits the mass of S8 produced by using the stoichiometry of the balanced chemical equation. In this case, 4 moles of SO2 will limit the production of S8, resulting in a maximum mass of 256g of S8 produced.
1/8 S8 + O2 --> SO2 , delta H degree f = -296.9 kJ
2h2s + so2 - 2h20 + 3s
S8 + 8 O2 → 8 SO2 burning sulfur in the presence of oxygen
The simplest reaction is: S + O2 = SO2
To balance the chemical equation for the reaction between Ba and S to produce BaS, you need to ensure that the number of atoms of each element is the same on both sides of the equation. You can balance the equation by adding coefficients in front of the Ba and BaS molecules. In this case, the balanced equation is: 8Ba + S8 -> 8BaS.
The chemical equation is:SF4 + 2 H2O = SO2 + 4 HF
To balance the equation SO2 + H2S = S + H2O, we need to ensure that there are equal numbers of each type of atom on both sides of the equation. Begin by placing coefficients in front of the compounds to balance the number of sulfur and hydrogen atoms, then balance the oxygen atoms last by adjusting the coefficient for H2O. The balanced equation is SO2 + 2 H2S = 3 S + 2 H2O.
To balance the equation SO2 + O2 -> SO3, you need to ensure the number of each type of atom is the same on both sides of the equation. Start by adding a coefficient of 1 in front of SO2 and O2, then balance the equation by adding a coefficient of 1 in front of SO3. This balances the equation as: 2SO2 + O2 -> 2SO3.
To balance the chemical equation CaO + SO2 → CaSO3, you need to add a coefficient of 1 in front of CaO and SO2. This balances the equation by ensuring that the same number of each type of atom is present on both sides.