0
What else can I help you with?
Why is the following equation invalid Al 2O2 --- Al2O3?
Because the numbers of aluminum and oxygen atoms are not the same on both sides of the equation, so the equation is not balanced. In order to be balanced, the numbers of atoms of each element must be the same on both sides of the equation. The correct equation is 4Al + 3O2 --> 2Al2O3. This gives 4 aluminum atoms and 6 oxygen atoms on both sides of the equation, so it is balanced.
How many aluminum atoms would there be on each side of the balanced equation?
To determine the number of aluminum atoms on each side of a balanced equation, you would need to examine the coefficients of the aluminum-containing compounds in the equation. Then, multiply the coefficient by the number of aluminum atoms in each compound. For example, in the equation 2Al + 3CuO → Al2O3 + 3Cu, there are 2 aluminum atoms on each side.
If 75 g of oxygen react how many grams of aluminum are required?
The balanced chemical equation for the reaction between aluminum and oxygen is 4Al + 3O2 → 2Al2O3. Using the stoichiometry of the equation, you would need 50 g of aluminum to react with 75 g of oxygen, since the molar ratio between Al and O2 is 4:3.
What is the balanced equation for sulfur oxygen and water?
The balanced equation for the reaction between sulfur, oxygen, and water is: Sulfur + Oxygen + Water → Sulfuric Acid
Given 18.32 grams of aluminum and excess oxygen how many grams of oxygen are used?
To determine the grams of oxygen used, we need to compare the moles of aluminum with the moles of oxygen in the reaction. The balanced chemical equation for the reaction between aluminum and oxygen is 4Al + 3O2 -> 2Al2O3. Using the molar mass of aluminum (26.98 g/mol) and oxygen (16.00 g/mol), we can calculate that 18.32 grams of aluminum would use 27.27 grams of oxygen in the reaction.
How do you balance the equation for aluminum and oxygen?
The balanced equation for aluminum and oxygen is: 4Al + 3O2 -> 2Al2O3. This balanced equation ensures that the number of atoms of each element is the same on both sides of the reaction arrow.
What is the coefficient for oxygen in the balanced equation of C5H12 plus O2 equals Co2 plus H2O?
The balanced equation is: C5H12 + 8O2 → 5CO2 + 6H2O. Therefore, the coefficient for oxygen in the balanced equation is 8.
What is the reaction for aluminium and oxygen?
The reaction between aluminum and oxygen forms aluminum oxide. The balanced chemical equation for this reaction is 4Al + 3O2 → 2Al2O3.
What is the theoretical yield of aluminum oxide if 3.40mol of aluminum metal is exposed to 2.85mol of oxygen?
The balanced chemical equation for the reaction between aluminum and oxygen to form aluminum oxide is: 4Al + 3O2 → 2Al2O3. From the balanced equation, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Therefore, if 3.40 mol of aluminum and 2.85 mol of oxygen are reacted, the limiting reactant is oxygen. Thus, 3.40 mol of aluminum would theoretically produce 1.90 mol of aluminum oxide.
What is the balanced formula equation when aluminum chlorate is heated?
The balanced formula equation when aluminum chlorate is heated is: 2 Al(ClO3)3(s) -> 2 AlCl3(s) + 9 O2(g)
Why is the following equation invalid Al 2O2 --- Al2O3?
Because the numbers of aluminum and oxygen atoms are not the same on both sides of the equation, so the equation is not balanced. In order to be balanced, the numbers of atoms of each element must be the same on both sides of the equation. The correct equation is 4Al + 3O2 --> 2Al2O3. This gives 4 aluminum atoms and 6 oxygen atoms on both sides of the equation, so it is balanced.
What is the coefficient on Al when equation is Al O2-Al2O3?
To balance the equation for the reaction of aluminum (Al) with oxygen (O2) to form aluminum oxide (Al2O3), we start with the unbalanced equation: 4Al + 3O2 → 2Al2O3. The coefficient on Al is 4 in this balanced equation, indicating that four aluminum atoms are needed to react with three molecules of oxygen to produce two formula units of aluminum oxide.
What is the balanced equation of sodium nitrate equals sodium nitrite plus oxygen?
2NaNO3 ==> 2NaNO2 + O2
What is the theoretical yield of aluminum oxide if 2.40 mole of aluminum metal is exposed to 2.10 mol of oxygen?
To determine the theoretical yield of aluminum oxide, we first need to write a balanced chemical equation for the reaction between aluminum and oxygen to form aluminum oxide. The balanced equation is 4Al + 3O2 -> 2Al2O3. From the equation, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Therefore, if 2.40 moles of aluminum is exposed to 2.10 moles of oxygen, the limiting reactant is oxygen. Using stoichiometry, we can calculate the theoretical yield of aluminum oxide, which is 1.60 moles.
In the equation for the reaction of potassium with oxygen what is the coefficient of oxygen in the balanced equation for this reaction?
The balanced equation for the reaction of potassium with oxygen is: 4K + O2 -> 2K2O The coefficient of oxygen in this balanced equation is 1.
What is the balanced symbol equation for potassium and oxygen?
The balanced symbol equation for potassium and oxygen is: 4K + O2 -> 2K2O
What is the Balanced symbol equation for carbon plus oxygen equals carbon dioxide?
The balanced symbol equation for carbon plus oxygen yielding carbon dioxide is: C + O2 -> CO2
