4NH3 + 5O2 -----> 4NO + 6HOH
3 O2(g) + 2 S(s) --> 2 SO3(g) (This turns into liquid below 45°C)
The balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) to form dinitrogen oxide (N2O) and water (H2O) is: 4NH3 + 5O2 → 4N2O + 6H2O
ammonia + oxygen --> nitrogen monoxide + water
Ca(ClO3)2 --> CaCl2 + 3O2 is the equation for calcium chlorate to calcium chloride + oxygen gas.
To calculate the number of grams of oxygen needed to react with 6.78 grams of ammonia, we first write out the balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) to form nitrogen monoxide (NO) and water (H2O). Then we use the stoichiometry of the equation to find the molar ratio between ammonia and oxygen. Finally, we convert the mass of ammonia to moles and then use the molar ratio to find the mass of oxygen needed.
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The balanced symbol equation for copper reacting with oxygen to form copper oxide is: 4Cu + O2 → 2Cu2O
The balanced equation for magnesium reacting with oxygen to form magnesium oxide is: 2Mg + O2 -> 2MgO
The balanced equation for the reaction is: 2CH3CHO + 3O2 -> 2CO2 + 2H2O
The balanced equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 5O2 → 4NO + 6H2O. To find the grams of oxygen needed to react with 23.9 grams of ammonia, you need to calculate the molar ratio between ammonia and oxygen using the balanced equation. Once you find the molar ratio, you can calculate the grams of oxygen required.
3 O2(g) + 2 S(s) --> 2 SO3(g) (This turns into liquid below 45°C)
The balanced chemical equation for phosphorus reacting with oxygen to form phosphorus pentoxide is: 4 P + 5 O2 -> P4O10
The balanced equation for the reaction of ammonia (NH3), oxygen (O2), and methane (CH4) to form hydrogen cyanide (HCN) and water (H2O) is: 4 NH3 + 3 O2 + CH4 → 2 HCN + 6 H2O
A balanced equation for reaction of ammonia with oxygen to form nitrogen monoxide and water is 4 NH3 + 5 O2 -> 4 NO + 6 H2O.
2h2s + o2 -> 2s + 2h2o
SO2 + O = SO3
The balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) to form dinitrogen oxide (N2O) and water (H2O) is: 4NH3 + 5O2 → 4N2O + 6H2O