of couse~ can....
even 2ml of water dissolve in 4.0 grams of copper sulfate.
Copper sulfatepentahydrate is a solid at 20 degrees Celsius has a density of 2.28g/cm3 (cubed)... and its' chemical symbol is CuSO4-5H2O
Copper sulfate in its solid crystal from present as pentahydrate (CuSO4 5 H2O). When heated strongly it loses water molecules and becomes CuSO4. Note that CuSO4 5 H2O is blue in color whereas CuSO4 is colourless since absorption region shifted from visible region. On further heating it is dissociated to CuO.
CuSO4.5H2O(s) --> CuSO4(s) + 5H2O(g)
penta = 5 copper(II) sulphate pentahydrate = CuSO4*5 H2O CuSO4*5 H2O + heat --> CuSO4 + 5 H2O
simply heat up the solvent (eg. water) till just below its boiling point and stir. the heating will allow more CuSO4 to dissolve as well but as the solution cools down some of the CuSO4 will come out of solution. you could also powder the CuSO4 to increase the surface area. This allows more contact between the solvent and the CuSO4, which increases the disolving speed.
Not completely sure what you're asking, but copper sulfate (CuSO4) will dissolve easily in water to form a cool-looking blue colored solution.(The term is dissolve).
yes
Copper sulfatepentahydrate is a solid at 20 degrees Celsius has a density of 2.28g/cm3 (cubed)... and its' chemical symbol is CuSO4-5H2O
hot water
hot water
Copper sulfate dissolves in water, it does not react.
Dissolve in water more than 320 g of the anhydrous salt, at 20 0C.
Copper sulfate in its solid crystal from present as pentahydrate (CuSO4 5 H2O). When heated strongly it loses water molecules and becomes CuSO4. Note that CuSO4 5 H2O is blue in color whereas CuSO4 is colourless since absorption region shifted from visible region. On further heating it is dissociated to CuO.
water and copper(II)sulfate CuO + H2SO4 --> CuSO4 + H2O
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
16.67
This equation is CuSO4.5 H2O -> CuSO4 + 5 H2O.