what is the color of aqueous sodium bromide? what is the color of aqueous sodium bromide?
I think this is right... Cl2 + 2NaBr = 2NaCl + Br2
The reaction between aqueous chlorine and sodium bromide solution results in the displacement of bromine by chlorine, forming sodium chloride and bromine gas as products. This is a redox reaction where chlorine is reduced and bromine is oxidized.
You would get Sodium Chloride and Bromine. This is because Chlorine is a more reactive group 7, (halogen), element that bromine, we know this because it is above bromine in the periodic table group, it is therefore more electronegative. When the reaction occurs, the Chlorine displaces the Bromine and the solution turns brown.
The binary ionic compound name for NaBr is sodium bromide.
There will be no colour change between the two, as chlorine is more electronegative than bromine and will maintain its negative charge, meaning that the bromine will not react and the orange colour persists.
The symbol equation for the reaction between chlorine and sodium bromide is: Cl2 + 2NaBr → 2NaCl + Br2.
When chlorine is added to sodium bromide solution, bromine is produced as one of the products through a redox reaction. The chlorine oxidizes the bromide ion to form bromine gas, while itself being reduced. This reaction is used to synthesize bromine from sodium bromide.
Sodium bromide is a white, crystalline solid.
The balanced chemical equation for this reaction is 2NaBr + Cl2 -> 2NaCl + Br2. It shows that one molecule of molecular chlorine reacts with two molecules of sodium bromide to produce two molecules of sodium chloride and one molecule of bromine.
I think this is right... Cl2 + 2NaBr = 2NaCl + Br2
The reaction between aqueous chlorine and sodium bromide solution results in the displacement of bromine by chlorine, forming sodium chloride and bromine gas as products. This is a redox reaction where chlorine is reduced and bromine is oxidized.
The ionic equation for the reaction between aqueous chlorine and aqueous sodium bromide is: Cl2(aq) + 2NaBr(aq) -> 2NaCl(aq) + Br2(aq)
Cl2 + 2NaBr -> 2NaCl + Br2
displacement reactiom
You would get Sodium Chloride and Bromine. This is because Chlorine is a more reactive group 7, (halogen), element that bromine, we know this because it is above bromine in the periodic table group, it is therefore more electronegative. When the reaction occurs, the Chlorine displaces the Bromine and the solution turns brown.
The reaction of bromine with sodium would be slower than the reaction of chlorine with sodium, as bromine is less reactive than chlorine. Both reactions would produce a salt (sodium bromide or sodium chloride) and release heat and gas (hydrogen gas in the case of chlorine).
The binary ionic compound name for NaBr is sodium bromide.