Chemical formulas:
- CuO, Cu(II)-oxide, cupric oxide (monocopper oxide), black
- Cu2O, Cu(I)-oxide, cuprous oxide (dicopper oxide), red
- sulfuric acid, H2SO4
CuO + H2SO4 --> CuSO4 + H2O , cupric sulfate, blue solution
Cu2O also reacts with dilute sulfuric acid forming CuSO4 by:
Cu2O + 2 H2SO4 --> CuSO4 + H2O + H2, cupric sulfate, blue solution
That makes a reaction beteween an base and an acid.
The chemical reaction is:
CuO + H2SO4 → CuSO4 + H2O
the reaction between sulphuric acid and copper oxide creates copper sulfate which has a blue color and blue copper sulfate pentahydrate crystals can be created.
Copper will not react with sulphuric acid, because copper is not reactive enough. Only metals which are higher than hydrogen in the reactivity series will react with sulphuric acid.
I think it makes Copper Sulfate
Copper carbonate + sulphuric acid = copper sulphate + water + carbon dioxide
Copper Oxide
Get copper suphate + carbon dioxide + water + residual of the original component not in the proper proportion.
There are two different copper oxide formula's:2Cu + O2 -> 2CuO (black Copper(II) oxide)or4Cu + O2 -> 2Cu2O (red Copper(I) oxide)
It is Sodium Sulphate :) Hope I helped
SO4H2 + 2Cu --> SO2 + 2CuOH
As in most chemical reactions, an increase in temperature increases the rate of reaction between copper oxide and acid.
CuOH + 3H2SO4 --> CuSO4 + 3H2O
Copper carbonate + sulphuric acid = copper sulphate + water + carbon dioxide
Balanced equation: CuO + 2HCl --> CuCl2 + H2O Word equation: One mole of copper (II) oxide plus two moles of hydrochloric acid produces (or yields) one mole of copper (II) chloride plus one mole of water.
Because the zinc is "oxydised" and the copper is "reduced"
oxygen
CuO + 2HCl --> CuCl2 + H2O
Copper Oxide
copper oxide.......CuO
Get copper suphate + carbon dioxide + water + residual of the original component not in the proper proportion.
Copper oxides are Cu2O - copper(I) oxide and CuO - copper(II) oxide.