Apparently, the first person who answered this question said ...'its easy find it out yourself'
Buh im just gunna tell yuh dah ....i dnt know miiself :)
The reaction between sodium and iron oxide would be a single displacement reaction, where sodium displaces iron from iron oxide to form sodium oxide and elemental iron. The balanced chemical equation for this reaction is 4Na + Fe2O3 -> 2Na2O + 2Fe.
The reaction between iron (II) chloride and sodium phosphate results in the formation of iron (II) phosphate and sodium chloride. The balanced chemical equation for this reaction is: FeCl2 + Na3PO4 → Fe3(PO4)2 + 6NaCl.
Iron Chloride + Sodium Hydroxide ------> Iron Hydroxide + Sodium Chloride Balanced reaction equations: FeCl3 + 3NaOH ------> Fe(OH)3 + 3NaCl or FeCl2 + 2NaOH ------> Fe(OH)2 + 2NaCl because iron can be either Iron(III)[Fe3+] or Iron(II)[Fe2+]
When iron chloride is mixed with sodium hydroxide, a double displacement reaction occurs. The iron chloride reacts with sodium hydroxide to form iron hydroxide and sodium chloride. The iron hydroxide precipitates out of the solution as a solid, leaving behind a clear liquid containing sodium chloride.
The reaction occurs because iron is more reactive then the copper is. The more reactive metal wants to create a compound, which is why it forms iron chloride. Copper, being the less reactive substance wants to become pure and separates from the chloride to be on its own.
When iron reacts with sodium chloride (NaCl), iron chloride (FeCl2) is formed. This reaction is a single displacement reaction where iron replaces sodium in the compound to form iron chloride and sodium is released.
In this reaction, sodium metal will replace iron in the iron chloride, forming sodium chloride and iron metal. This is an example of a single displacement reaction, where a more reactive element displaces a less reactive element in a compound.
Iron (II) chloride and sodium hydroxide react to produce iron (II) hydroxide and sodium chloride. FeCl2(aq) + NaOH(aq) --> Fe(OH)2(s) + NaCl(aq) This is a double replacement/displacement reaction.
The reaction between sodium and iron oxide would be a single displacement reaction, where sodium displaces iron from iron oxide to form sodium oxide and elemental iron. The balanced chemical equation for this reaction is 4Na + Fe2O3 -> 2Na2O + 2Fe.
The reaction between iron (III) chloride and sodium hydroxide is a chemical change as new substances are formed. Iron (III) hydroxide and sodium chloride are produced as a result of the reaction.
Iron (III) chloride reacts with sodium hydroxide to form iron (III) hydroxide and sodium chloride in a double displacement reaction. The balanced chemical equation is 2FeCl3 + 6NaOH → 2Fe(OH)3 + 6NaCl.
Iron doesn't react with sodium chloride but rusting is accelerated in salted water.
It is Iron III hydroxide (thats the brick red precipitate). It forms as well sodium chloride which is soluble in the water of the reaction and therefore you do not see.
Reaction_of_ferric_chloride_to_sodium_hydroxideBasically: FeCl3 (ferric chloride) + 3NaOH (sodium hydroxide) > Fe(OH)3 + 3NaCl (ferric hydroxide precipitate and sodium chloride, respectively)
iron chloride + sodium hydroxide = sodium chloride +iron hydroxide
Yes. According to the activity series of metals, the calcium will replace the iron in the iron chloride compound, forming calcium chloride and iron. Refer to the related link for an activity series of metals.
Yes, iron will react with copper chloride solution to form iron chloride and copper metal. This is a single displacement reaction where iron displaces copper from the chloride solution.