Sort of. Lithium loses one electron in order to achieve the noble gas configuration of helium, which has only two valence electrons in its 1s sublevel. The octet rule refers to the fact that atoms share or transfer electrons in order to achieve a noble gas configuration with eight valence electrons, called an octet. Helium is an exception to the rule.
PF5 obeys the octet rule as it has 5 bonding pairs of electrons around the central phosphorus atom, satisfying the octet. Cs2 does not follow the octet rule as Cs is in Group 1 and can only form ionic bonds. BBr3 is an exception to the octet rule as boron has only 6 electrons around it due to the empty d orbital. CO3 2- also obeys the octet rule as each oxygen atom has a complete octet.
No, MgCl2 does not follow the octet rule. Magnesium typically forms ionic bonds with a 2+ charge, so in MgCl2, magnesium has only 8 electrons in its outer shell (2 from Mg and 6 from 2 Cl atoms), not a full octet.
Lithium donates an electron to fluorine, forming lithium cations and fluorine anions that attract each other via ionic bonds. This results in the formation of lithium fluoride, a stable compound that satisfies the octet rule for both lithium and fluorine.
Boron atoms do not follow the octet rule. This is because boron typically forms compounds with fewer than 8 electrons around it due to its atomic structure. Boron forms stable compounds by sharing electrons in covalent bonds and can have as few as 6 electrons in its valence shell.
See the Related Questions to the left for how to solve this problem.First draw the Lewis Dot structures of each molecule, then count the valence electrons of each atom in the structures. Find the one that doesn't have eight!In this case, there is actually a little trick. To follow the octet rule, each atom must have 8 valence electrons in the structure, right? Therefore, the molecule must have an even number of total electrons for that to work. So which molecule does not have an even number of total electrons?
no it does not follow octet rule
octet rule
No, BCl3 does not follow the octet rule as boron only has 6 valence electrons in this molecule. Boron can form stable compounds with less than an octet due to its electron deficiency.
Boron trichloride does not follow the octet rule. Boron does not allow the eight required electrons in the outer shell.
No, AsH3 does not follow the octet rule. Arsenic, the central atom in AsH3, can expand its valence shell to hold more than eight electrons in bonding.
yes PCl3 obey octet rule there are 5 electrons in the valence shell of phosphorous it need 3 electron to complete its octet so it form bond with 3 chlorine after bond formation there are 8 electron in its octet it obey octet rule
Of course it does obey.There are 8 electrons around Nitrogen.
H2S does follow the octet rule. When you draw the Lewis Structure for H2S, it looks like this: If you count up the lone pairs and sigma bonds (each worth 2), there are 8, thus, H2S follows the octet rule.
The octet rule is a rule in chemistry where elements want to form bonds to attain 8 electrons in their valence shell. An example of this would be sodium chloride. Bonds that don't have 8 electrons in their valence shell don't follow this rule
An example of a molecule that follows the octet rule is methane (CH4). In methane, carbon forms four covalent bonds with hydrogen, allowing each atom to achieve a full outer shell of electrons (octet) and satisfy the octet rule.
Hydrogen is the atom that doesn't always obey the octet rule. It only needs 2 electrons to have a full outer shell, rather than the 8 electrons typically required by the octet rule. Oxygen and bromine usually follow the octet rule.
No, AlCl3 does not follow the octet rule. Aluminum typically forms compounds where it only has 6 electrons in its outer shell, such as in AlCl3 where it forms 3 bonds with chlorine atoms.