C4H16BR4.
Limonene adds 4Br and the two double bond is broken.
That seems to be known most commonly as the bromine test for unsaturated bonds. Historically the reaction may have been most commonly associated with Parker McIlhiney who developed means for performing assays based on it.
There is no such compound named Phosphorus bromine. It you refer to the product formed in the reaction of phosphorus and bromine, its Phosphorus Tribromide = PBr3
it cant decolourise
you find yourself
Sunlight wouldn't be enough energy to carry out the reaction between n-hexane and bromine. The energy source, however, may have been written has "hv" as a way to describe the radiation or high-wavelength energy for the reaction, which is possible in a more controlled environment. In this scenario, the reaction between n-hexane and bromine is a bromination reaction--generation of a bromine radical and attaching one or more bromine molecules to hexane. It is more likely that it will attach to a secondary carbon rather its primary, and its location of attachment between the available secondary carbons would be a mixture.
That seems to be known most commonly as the bromine test for unsaturated bonds. Historically the reaction may have been most commonly associated with Parker McIlhiney who developed means for performing assays based on it.
The reaction between methane and bromine is a photochemical reaction. Refer to the related link below.
There is no such compound named Phosphorus bromine. It you refer to the product formed in the reaction of phosphorus and bromine, its Phosphorus Tribromide = PBr3
Any reaction occur between neon and bromine.
Well, if your talking about the reaction between sodium bromide (NaBr) and Iodine, then I don't think that it will replace bromine. Bromine is higher on the reactivity series, so if they come into contact with each other, there won't simply be any reaction
CCL4 is a carrier for Bromine reaction.
it cant decolourise
you find yourself
Sunlight wouldn't be enough energy to carry out the reaction between n-hexane and bromine. The energy source, however, may have been written has "hv" as a way to describe the radiation or high-wavelength energy for the reaction, which is possible in a more controlled environment. In this scenario, the reaction between n-hexane and bromine is a bromination reaction--generation of a bromine radical and attaching one or more bromine molecules to hexane. It is more likely that it will attach to a secondary carbon rather its primary, and its location of attachment between the available secondary carbons would be a mixture.
Sodium and bromine are chemical elements, not properties; the chemical reaction between sodium and bromine is a chemical process, not a property.
MgBr2 (magnesium bromide) would be the most favorable reaction between magnesium and bromine.
The formula for bromine triflouride is BF3.