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The chemical formula for copper (I) iodide is CuI, and for copper (II) iodide is CuI2. Copper (I) iodide is the more common of the two.

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16y ago

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Related Questions

What is formula for cupric iodide?

The chemical formula for cupric iodide is CuI2. It is composed of one copper (Cu) ion and two iodine (I) ions.


What is the formula for nickel (ii) iodide?

The formula for nickel(II) iodide is NiI2.


How many atoms of each are in copper iodide?

Copper iodide has one copper atom and one iodide atom in its chemical formula, which is CuI.


What is the correct name for this compound Cui2?

The correct name for the compound CuI2 is copper (II) iodide. It is formed by the combination of a copper ion with a +2 charge and two iodide ions.


What elements make up copper iodide?

Copper iodide is a chemical compound composed of copper and iodine atoms. Its chemical formula is CuI.


What is the chemical compound name for Cul2?

The chemical compound name for CuI2 is copper(II) iodide. It is composed of copper ions with a +2 oxidation state and iodide ions.


What is the formula for mercury2 iodide?

Mercury(II) iodide is HgI2.


What is the formula Hgl2?

Mercury(I) iodide (HgI2) is the chemical formula for solid mercury iodide.


How is cuprous iodide prepared?

React a solution of Copper(II) sulfate with Sodium Iodide. It will produce Copper(II) Iodide and Sodium sulfate. This Copper(II) iodide, due to instability, spontaneously decomposes, producing Iodine and Copper(I) Iodide.The Copper(I) iodide comes out as a yellowish brown precipitate. So the overall reaction seems to be:2 CuSO4 + 4 NaI ----> 2 CuI + 2 Na2SO4 + I2


Formula for Mercury iodide?

Mercury(I) iodide = Hg2I2 Mercury(II) iodide = HgI2


What is the formula name for CuI2?

The formula name for CuI2 is copper(I) iodide.


When leadII nitrate reacts with sodium iodine what is the correct formula for the product ledII iodine?

The correct formula for the product of lead(II) nitrate reacting with sodium iodide is lead(II) iodide, which has the formula PbI2. This is because lead(II) ions from lead(II) nitrate react with iodide ions from sodium iodide to form lead(II) iodide as the product.