No. The correct one is CO + H2O ----> HCOOH (Formic acid)
P4+Cl2 P4+Cl2
4 HCl + O2 = 2 H2O + 2 Cl2.
Ammonium Iodide solution.
KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 After you balance it: 2KMnO4 + 16HCl = 5Cl2 + 8H2O + 2KCl + 2MnCl2
3(Cl2) + 3(H2O) = 5(HCl) + 1(HClO3)
Cl2 + 2NaOH ----> NaCl + NaClO + H2O or Cl2 + 2OH- ----> Cl- + ClO- + H2O
HCl + NaOH = H2O + NaCl is already balanced.
c4 +H10 --->CO+ H2O
Yes, very. <- This does not answer the question appropriately.
No they are not the products.Product is as this. H2SO3
NaClO3 + 6 HCl = 3 Cl2 + 3 H2O + NaCl
cl2o7+h2o
No. The correct one is CO + H2O ----> HCOOH (Formic acid)
P4+Cl2 P4+Cl2
K2Cr2O7+14HCl ---> 3Cl2 + 2CrCl3 + 2KCl + 7H2O
NaCl plus CaCO3 plus water