answersLogoWhite

0

How to prepare 0.1M 100mL AgNo3 (MW = 169.8731 g/mol)

So, what we have is,

M=0.1M

V=100mL/0.1L

MW=169.8731g/mol

Weight = ?

Formula:-

mol = M x V = Weight / MW

thus weight = M x V x MW

= 0.1 x 0.1 x 169.8731 (mol/L x g/mol x L)

= 1.69g

Measure 1.69g of AgNO3 and put inside a 100mL volumetric flask. top up with distilled H2O until 100mL. Siap!

User Avatar

Wiki User

15y ago

What else can I help you with?