How to prepare 0.1M 100mL AgNo3 (MW = 169.8731 g/mol)
So, what we have is,
M=0.1M
V=100mL/0.1L
MW=169.8731g/mol
Weight = ?
Formula:-
mol = M x V = Weight / MW
thus weight = M x V x MW
= 0.1 x 0.1 x 169.8731 (mol/L x g/mol x L)
= 1.69g
Measure 1.69g of AgNO3 and put inside a 100mL volumetric flask. top up with distilled H2O until 100mL. Siap!
The strength of a solution may be described as a percentage or volume, where 1% hydrogen peroxide releases 3.3 volumes of oxygen during decomposition.Thus, a 3% solution is equivalent to 10 volume and a 6% solution to 20 volume, etc. Answer taken from Wikipedia 19/01/2009
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