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Equations of ethyl iodide plus alcoholic potash?
The reaction between ethyl iodide and alcoholic potash (potassium hydroxide dissolved in alcohol) results in the formation of ethyl alcohol, potassium iodide, and potassium ethoxide. The chemical equation for this reaction can be written as: C2H5I + KOH → C2H5OH + KI + KOC2H5
Product of alcoholic silver nitrate with ethyl bromide reaction?
When ethyl bromide, an alkyl halide, reacts with alcoholic silver nitrate (AgNO3), silver bromide (AgBr) and ethanol are produced. This reaction is a substitution reaction where the bromine in ethyl bromide is replaced by the nitrate ion from silver nitrate.
What is the Latent heat of vaporization for ethyl acetate?
The latent heat of vaporization for ethyl acetate is approximately 28.44 kJ/mol. This is the amount of energy required to convert one mole of liquid ethyl acetate into vapor at its boiling point.
What is the symbol of iodide?
Iodide is iodine with a negative charge, and is thus written as I-.
What is the other term for silver iodide?
Silver(I) iodide
What is the reaction if ethyl iodide and potassium acetate?
Ethyl iodide will undergo an SN2 reaction with potassium acetate to form ethyl acetate and potassium iodide. This reaction involves the substitution of the iodine atom in ethyl iodide with the acetate ion from potassium acetate.
What is the volume of 24 mmol of ethyl iodide and the theoretical yield of p-ethoxynitrobenzene?
The volume of 24 mmol of ethyl iodide would depend on its density, which is about 2.29 g/cm³. To calculate the volume, you would need to convert 24 mmol to grams using the molar mass of ethyl iodide (155.99 g/mol) and then divide by the density. The theoretical yield of p-ethoxynitrobenzene would depend on the reaction conditions and stoichiometry of the reaction involving ethyl iodide, but you would use the molar ratio of ethyl iodide to p-ethoxynitrobenzene to calculate the theoretical yield.
What solvents are soluble in ethyl iodide?
Ethyl iodide is miscible with ethanol.
What is chemical equation ethyl iodide plus aq.KOH?
The chemical equation for the reaction between ethyl iodide and aqueous potassium hydroxide is: C2H5I + KOH → C2H5OH + KI This reaction involves the substitution of the iodine in ethyl iodide with hydroxide from KOH, resulting in the formation of ethanol and potassium iodide.
How many ethene be converted into ethyl alcohol?
One. Ethene [also ethylene] [H2C=CH2] plus H2O yields H3C-CH2OH [ethanol].
What is the volume of 24 mol of ethyl iodide and the theoretical yield of p-ethoxynitrobenzene?
The volume of 24 mol of ethyl iodide is 1,929 L.
What has the author Ralph Eugene Plump written?
Ralph Eugene Plump has written: 'A study of reaction products and mechanism in the electrolytic reduction of ethyl iodide' -- subject(s): Electrolytic reduction, Ethyl iodide
Is ethyl iodide polar?
Yes, ethyl iodide is polar. The molecule has a slight positive charge on the carbon atom due to the iodine's higher electronegativity, leading to an uneven distribution of electrons and creating a polar molecule.
What base is used in the alkylation of methyl hexanoate with ethyl iodide?
The base commonly used in the alkylation of methyl hexanoate with ethyl iodide is usually a strong base like sodium hydride (NaH) or potassium tert-butoxide (KOtBu). These bases are effective in promoting the deprotonation of the acidic hydrogen on the ester, allowing for the subsequent nucleophilic attack by the ethyl iodide.
Name the addition product formed by ethene and water?
The addition product formed by ethene and water is ethanol. This reaction involves the addition of a water molecule across the carbon-carbon double bond in ethene, resulting in the formation of ethanol.
What happens when ethanol is treated with HI in presence of red phosphorus?
The ethyl iodide is formed.
Equations of ethyl iodide plus alcoholic potash?
The reaction between ethyl iodide and alcoholic potash (potassium hydroxide dissolved in alcohol) results in the formation of ethyl alcohol, potassium iodide, and potassium ethoxide. The chemical equation for this reaction can be written as: C2H5I + KOH → C2H5OH + KI + KOC2H5
