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How do you find the molar mass of beryllium oxide?
To find the molar mass of beryllium oxide (BeO), you will need to determine the individual molar masses of beryllium (Be) and oxygen (O) from the periodic table and then add them together. The molar mass of Be is about 9 g/mol and the molar mass of O is about 16 g/mol. When you add them together, you'll find that the molar mass of BeO is approximately 25 g/mol.
What is the mass of 24.6 formula units of magnesium oxide?
To find the mass of 24.6 formula units of magnesium oxide, we first need to determine the molar mass of magnesium oxide. Magnesium has a molar mass of approximately 24.3 g/mol, and oxygen has a molar mass of approximately 16.0 g/mol. Therefore, the molar mass of magnesium oxide (MgO) is 24.3 + 16.0 = 40.3 g/mol. Next, we multiply the molar mass of MgO by the number of formula units (24.6) to find the total mass: 40.3 g/mol x 24.6 = 992.38 grams. Therefore, the mass of 24.6 formula units of magnesium oxide is approximately 992.38 grams.
What is the empirical formula of an iron oxide that 65.0 percent fe and 35.0 percent O?
The empirical formula of the iron oxide compound is Fe₂O₃. This is determined by dividing the percentage of each element by its molar mass to find the ratio of atoms in the compound.
What is the percent composition of the compound formed when 2.70 g of aluminum combine with oxygen to form 5.10 g of aluminum oxide?
The molar mass of aluminum oxide is 101.96 g/mol. To find the percent composition, divide the mass of each element by the molar mass of the compound and multiply by 100. The percent composition is 52.72% aluminum and 47.28% oxygen.
How many grams of calcium oxide are needed to produce 36.0 g of hg?
To calculate the amount of calcium oxide needed to produce 36.0 g of mercury (Hg), we need to first determine the molar ratio between calcium oxide and mercury. The molar ratio can be determined from the balanced chemical equation of the reaction. Once the molar ratio is known, we can use it to find the amount of calcium oxide needed to produce 36.0 g of mercury.
How do you find the molar mass of beryllium oxide?
To find the molar mass of beryllium oxide (BeO), you will need to determine the individual molar masses of beryllium (Be) and oxygen (O) from the periodic table and then add them together. The molar mass of Be is about 9 g/mol and the molar mass of O is about 16 g/mol. When you add them together, you'll find that the molar mass of BeO is approximately 25 g/mol.
What is the mass of 24.6 formula units of magnesium oxide?
To find the mass of 24.6 formula units of magnesium oxide, we first need to determine the molar mass of magnesium oxide. Magnesium has a molar mass of approximately 24.3 g/mol, and oxygen has a molar mass of approximately 16.0 g/mol. Therefore, the molar mass of magnesium oxide (MgO) is 24.3 + 16.0 = 40.3 g/mol. Next, we multiply the molar mass of MgO by the number of formula units (24.6) to find the total mass: 40.3 g/mol x 24.6 = 992.38 grams. Therefore, the mass of 24.6 formula units of magnesium oxide is approximately 992.38 grams.
What is the number of moles of copper oxide in 7.95g copper oxide?
To find the number of moles, you need to divide the mass of copper oxide by its molar mass. The molar mass of copper oxide (CuO) is approximately 79.55 g/mol. Therefore, 7.95g of copper oxide is equal to 0.1 moles (7.95g / 79.55 g/mol).
If 5 grams of oxygen combines with 37.2 grams of uranium to form uranium oxide how many grams of the oxide are formed?
To find the grams of uranium oxide formed, we need to determine the molar mass of uranium and oxygen, calculate the moles of each element present, and finally the moles of uranium oxide formed. Then, we convert moles to grams using the molar mass of uranium oxide. The final answer for the grams of uranium oxide formed depends on the stoichiometry of the reaction.
how many moles of Aluminium oxide are in 12.75g of aluminium oxideNeed to know?
To determine the number of moles of aluminum oxide in 12.75g of aluminum oxide, you first need to find the molar mass of aluminum oxide, which is 101.96 g/mol. Then, divide the given mass (12.75g) by the molar mass to find the number of moles. So, 12.75g / 101.96 g/mol ≈ 0.125 moles of aluminum oxide.
What is the empirical formula of an iron oxide that 65.0 percent fe and 35.0 percent O?
The empirical formula of the iron oxide compound is Fe₂O₃. This is determined by dividing the percentage of each element by its molar mass to find the ratio of atoms in the compound.
What is the percent composition of the compound formed when 2.70 g of aluminum combine with oxygen to form 5.10 g of aluminum oxide?
The molar mass of aluminum oxide is 101.96 g/mol. To find the percent composition, divide the mass of each element by the molar mass of the compound and multiply by 100. The percent composition is 52.72% aluminum and 47.28% oxygen.
How many grams of calcium oxide are needed to produce 36.0 g of hg?
To calculate the amount of calcium oxide needed to produce 36.0 g of mercury (Hg), we need to first determine the molar ratio between calcium oxide and mercury. The molar ratio can be determined from the balanced chemical equation of the reaction. Once the molar ratio is known, we can use it to find the amount of calcium oxide needed to produce 36.0 g of mercury.
How many formula units are in 4.89 mil of sodium oxide?
To determine the number of formula units in 4.89 moles of sodium oxide, you need to first calculate the molar mass of sodium oxide (Na2O). The molar mass of Na2O is 61.98 g/mol. Next, you convert 4.89 moles to grams by multiplying by the molar mass. Finally, divide the mass by the molar mass of Na2O to find the number of formula units, which is approximately 4.34 x 10^23 formula units.
A particular element M has a heat capacity of 0.36 JgK and it forms an oxide that contains 2.9 grams of M per gram of oxygen What is the molar mass of the metal?
To find the molar mass of the metal (M), first, calculate the molar mass of the oxide. Since one gram of the oxide contains 2.9 grams of M and 1 gram of oxygen, the molar mass of the oxide is M + O = 2.9M + 16. Using the heat capacity, you can calculate the molar mass of the oxide, which in turn gives you the molar mass of the metal M.
How do you find molar mass of Aluminum Oxide Al2O3 in grams?
To find the molar mass of Aluminum Oxide (Al2O3), you need to add the molar masses of the individual elements. The molar mass of aluminum (Al) is approximately 27 g/mol, and the molar mass of oxygen (O) is approximately 16 g/mol. Therefore, the molar mass of Al2O3 is (227) + (316) = 102 g/mol.
How many moles are in 28 grams of calcium oxide?
To find the number of moles in 28 grams of calcium oxide, we need to divide the given mass by the molar mass of calcium oxide. The molar mass of calcium oxide (CaO) is 56.08 g/mol. So, 28 grams of CaO is equal to 28 g / 56.08 g/mol = 0.5 moles of calcium oxide.
