acetone + ethyl magnesium bromide = 2-methyl-2-butanol
First, ethyl bromide can be converted to ethyl magnesium bromide. Then, ethyl magnesium bromide can react with carbon dioxide to form propionic acid. Hydrolysis of the resulting compound will yield propionic acid.
The reaction between 1-propanol and ethyl bromide would result in an SN2 reaction where the ethyl bromide attacks the carbon bearing the -OH group on 1-propanol, displacing the hydroxyl group and forming ethyl propyl ether as the main product. Sodium hydroxide may be used as a catalyst in this reaction.
When ethyl bromide, an alkyl halide, reacts with alcoholic silver nitrate (AgNO3), silver bromide (AgBr) and ethanol are produced. This reaction is a substitution reaction where the bromine in ethyl bromide is replaced by the nitrate ion from silver nitrate.
The reaction between ethanol and bromine produces ethyl bromide as the main product. The reaction involves the substitution of a hydrogen atom in ethanol by a bromine atom, resulting in the formation of a molecule of ethyl bromide.
The rate of disappearance of ethyl bromide would decrease if the solution were diluted by adding an equal volume of pure ethyl alcohol. This is because the concentration of ethyl bromide would decrease, resulting in fewer ethyl bromide molecules available for the reaction. The rate of reaction is directly proportional to the concentration of reactants, so decreasing the concentration would slow down the rate of disappearance.
First, ethyl bromide can be converted to ethyl magnesium bromide. Then, ethyl magnesium bromide can react with carbon dioxide to form propionic acid. Hydrolysis of the resulting compound will yield propionic acid.
The reaction between 1-propanol and ethyl bromide would result in an SN2 reaction where the ethyl bromide attacks the carbon bearing the -OH group on 1-propanol, displacing the hydroxyl group and forming ethyl propyl ether as the main product. Sodium hydroxide may be used as a catalyst in this reaction.
To convert ethyl magnesium bromide into ethanol, you would first react it with water or a suitable proton source (such as an alcohol) to yield the corresponding alcohol. In this case, adding water to ethyl magnesium bromide would give ethanol. The reaction must be done carefully due to the high reactivity of the Grignard reagent.
Methyl bromide cannot be directly converted into ethyl bromide. However, methyl bromide can be converted into ethyl bromide through a substitution reaction by reacting it with ethyl alcohol in the presence of a strong base, such as sodium hydroxide, to form ethyl bromide.
THIS IS A DIRECT QUOTE FROM YAHOO ANSWERS:Benzene and magnesium hydroxide and magnesium bromide.I am betting you are doing a Grignard reactionEthyl benzoate + 2 phenylmagnesium bromide --> triphenylmethanol•MgBr saltif water is present, the grignard reacts with the water firstPhenylmagnesium bromide + H2O --> benzene + MgOHBr
ethyl bromide is C2H5Br
When ethyl bromide, an alkyl halide, reacts with alcoholic silver nitrate (AgNO3), silver bromide (AgBr) and ethanol are produced. This reaction is a substitution reaction where the bromine in ethyl bromide is replaced by the nitrate ion from silver nitrate.
Ethyl bromide can be converted into butane through a series of steps involving elimination reactions. The ethyl bromide can be treated with a strong base, such as sodium ethoxide, to form ethylene gas. Ethylene gas can then be subjected to a hydrogenation reaction to produce butane.
Propane is prepared from ethyl bromide through a series of chemical reactions. Ethyl bromide is first treated with metallic sodium to form diethyl ether. This diethyl ether is then dehydrated to form ethylene, and ethylene is subsequently hydrogenated to produce propane.
The reaction between ethanol and bromine produces ethyl bromide as the main product. The reaction involves the substitution of a hydrogen atom in ethanol by a bromine atom, resulting in the formation of a molecule of ethyl bromide.
The rate of disappearance of ethyl bromide would decrease if the solution were diluted by adding an equal volume of pure ethyl alcohol. This is because the concentration of ethyl bromide would decrease, resulting in fewer ethyl bromide molecules available for the reaction. The rate of reaction is directly proportional to the concentration of reactants, so decreasing the concentration would slow down the rate of disappearance.
Pure magnesium is a metal and the bonding is not covalent. Magnesium forms ionic bonds with more electronegative elements and this is its most common method of bonding. It does form covalent bonds for example with carbon in grignard reagents, for example ethyl magnesium bromide, C2H5MgBr.