How do you prepare phosphate buffer solution of pH 6.8?

Answer 1

Phosphate buffer pH 6.8 preparation protocol below

Stock solutions:

0.2M dibasic sodium phosphate (1 liter)

Na2HPO4*12H2O (MW=358.14) --------71.64gm + dH2O to make 1 liter (Solution X)

0.2M monobasic sodium phosphate (1 liter)

NaH2PO4*H2O (MW=138.01) --------27.6gm + dH2O to make 1liter (Solution Y)

Working buffer: 0.1M (1 liter)

pH 6.8 245 ml solution X + 255 ml solution Y ( filled up to 1 liter with dH2O)

Answer 2

Try using this equation:

(F.W. with unit g/mol)(Molarity with unit mol/L)(vol. needed with unit L) = amt. reagent needed with unit g

After the potassium is measured and your solution is made (minus a small amount of water for pHing), check the pH. Adjust pH according. Que solution up to final volume.

Answer 3

First, you have to prepare Phosphate Buffer A by diluting 31.2 grams NaH2PO4*2H20 to 1000mL. Second, prepare Phosphate Buffer B by diluting 53.61 grams Na2HPO4*7H20 (You can also use Na2HPO4 or Na2HPO4*12H20, but the amount to be used is different, so you have to compute for it) to 1000mL. Then, mix 62.5% of Buffer A with 37.5% of Buffer B. Adjust the PH using NaOH and H2PO4.

Answer 4

Dissolve 90g of NaHPO4.H2O in 500 ml of water. After complete

dissolution add 32.7 g of dibasic phosphate (Na2HPO4, 99.5%) and stir the mixture until totally dissolved. You can verify the pH using a pH meter. Dilute NaOH or H3PO4 can be added to adjust the pH if necessary.

Answer 5

To prepare a phosphate buffer solution of pH 6.8, you would mix sodium dihydrogen phosphate (monobasic) and disodium hydrogen phosphate (dibasic) in the appropriate ratio to achieve the desired pH. The exact ratio will depend on the concentrations of the two salts and the volume of water used in the solution. Additionally, you would need to use a pH meter or pH strips to verify and adjust the pH as needed.

Answer 6

1. Make 0.3M K2HPO4 or Na2HPO4

2. Make 0.3M KH2PO4 or NAH2PO4

3. Carefully mix Sodium/Potassium mono- and dibasic- phosphate solutions so that pH is 6.0

Answer 7

This equation should work with the above measurements.

(F.W. with unit g/mol)(Molarity with unit mol/L)(vol. needed with unit L) = amt. reagent needed with unit g

Answer 8

100 mL 0,05 M KH2PO4 + 44,8 mL 0,05 NaOH