How long will it take a 50 Watt heater to melt 100 grams of ice at 0 degree Celsius with steps?

Answer 1

680 seconds

Answer 2

SuggestionIf the freezing point of H2O is 0 degrees C, then any temperature over that will start to melt the ice. The more heat, the quicker it will melt.

...it takes 1.67x10^7 Joules

...1.67x10^4 KiloJoules

3.99x10^6 calories

3.99x10^3 Calories

Answer 3

You take the heat of fusion for H2O, which is 333 J/g. So it take 333 Joules to melt one gram of Ice. There fore you take the 51.4 g of Ice and times it by the 333 J/g to get 17116.2 J, or 17.12 KJ

Answer 4

Here's how I did it.

(1) You need to find the amount of heat to change the water from ice to a liquid at 0oC. To do this you need to find out the number of moles of water you have and you need the heat of fusion (melting).

5 g H2O * (1 mol H2O / 18 g H2O) = 0.278 mol H2O

Hfusion = 6.0095 KJ/mol (I looked this up in a Chemical Engineering book)

H = 0.278 mol & 6.0095 kJ/mol = 1.671 kJ

(2) Next you need to determine how much heat is required to raise the temperature of the liquid from 0oC to 50oC. To do that you need the heat capacity of water Cp. You can look this up in an engineering hanbook & use the equation below:

H = n*Cp*(T2-T1) Cp = 0.0754 kJ/(mol*oC)

= (0.278 mol) * (0.0754 kJ/mol*oC) * (50 - 0oC)

= 3.77 kJ

Add the two answers from (1) & (2) to get 5.44 kJ.

Answer 5

It takes 80 calories to raise one gram of water by one degree Celsius. Then to raise 50 grams by 1 degree takes 4 kilocalories.

Answer 6

The melting of ice is a physical change from a solid state into a liquid state. The amount of heat required to melt 50 g of ice is 16,744 Joules.

Answer 7

the answer is 680 seconds but what are the the steps to derive the answer

Answer 8

You need the Delta H fusion for water. Multiply that by 50 grams. Then multiply 50 g x 4.184 x 65 to get joules to raise water to 65 degrees. Add these values together to get total joules.

Answer 9

50 x 80 = 4000 calories

Answer 10

50W = 50J/sec.

Use formula

Q = m×latent heat of fusion(ice).

= 100× 340

=34000J

Now,

50J ----1second

34000J------?seconds

=34000÷50

=680 seconds