0.001167 kWh/°C/l at 100% efficiency.
My 100l has a standing loss of 2kwh and my 200l is 3kwh.
The electric meter uses kWh (kilowatt x hours) as units; a Joule is a watt x second. Therefore, a kWh has 3.6 million joules. Just multiply by this number.
Energy is measured in Joules and is generally defined as the potential to do work. Power is the rate of energy usage (Watts) or (Joules per second). A kWh is also a unit of energy (1000 W * 3600 seconds = 3600000 J)
50000 to 100000 Kw/ unit
1 megawatt is 1000 kilowatts, and there are 31 x 24 = 744 hours in a month and 1 hr =60X60 sec, so in a month (31 days) we would get (1000X24X31)KWh=744 X103 KWH
1 gallon of water weighs 8.34 pounds. It takes I BTU to change the temp of 1 pound of water 1 degree F. So for 1 gallon it takes 8.34 BTU. It takes 3412.14 BTU to equal 1 KWH. So 8.34 Btu x (1KWH / 3412.14 BTU) = 0.002444 KWH
To raise the temperature of one cc of water requires i calorie of heat . you did not specify the volume.
kWh stands for kiloWatthours, the amount of electrical energy an appliance uses or generates in one hour measured in kiloWatts. It has nothing to do with one cubic metre of water.
1 mwh = 1000 kwh hence 4 mwh = 4000 kwh
100 kWh
1 kwh = 3,600,000 Joules
about 10,000 KWh
1 PJ equals 277 777 777.78 kWh
approximately 40 kWh
To find kWh a time frame has to be given. That is what the h in kWh stands for.
Dinorwig is a 'pumped storage' hydro power facility. It has a capacity to produce 1.89GW of electricity, which equates to 6.8TWh. I terms of kWh, this would be 6.8E9 kWh or 6,800,000,000 kWh. (6.8 billion kWh).
Hi I believe it is 277.7 kWh per Gj. Cheers