How many atoms are present in 7.92g of calcium fluoride?

Answer 1

7.92 grams calcium fluoride (1 mole CaF2/78.08 grams)(6.022 X 1023/1 mole CaF2)

= 6.11 X 1022 atoms of calcium fluoride

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Answer 2

Calculate the number of moles of calcium fluoride by dividing the mass by its molar mass. The molar mass of calcium fluoride (CaF2) is 78.08 g/mol. Then, multiply the number of moles by Avogadro's number (6.022 x 10^23) to find the number of atoms present in 7.92g of calcium fluoride.