The number of atoms is 33.
11 atoms and 44molecules
11 atoms
?
The chemical formula (not symbol) of calcium bicarbonate is Ca(HCO3)2.
In 3Ca(OH)2 there are three Ca(OH)2 - (Calcium hydroxide) moleculesIn one Ca(OH)2 there is one Calcium, and two (OH) units. In one (OH) unit there is one Oxygen and one Hydrogen. With the above information it evident that there are 5 atoms in one Ca(OH)2 molecule and as there are 3 of these molecules present, there would be a total of 15 atoms present in 3Ca(OH)2
The formula is not charge balanced. Meaning the Ca has a 2+ charge and the HCO3 has a net 1- charge. Thus, the formula is incorrect. If you remove the Hydrogen you make CO3 a 2- charged anion giving you CaHCO3 (Calcuim carbonate), or the Ca can bond with two HCO3 (hydrogen carbonate) anions to form Ca(HCO3)2 (Calcium bicarbonate)
Amount of Ca = 181/40.1 = 4.51mol 1 mol of Ca contains 6.02 x 1023 Ca atoms. Therefore 4.51 mol of Ca will contain 4.51 x 6.02 x 1023 = 2.72 x 1024 atoms.
Calcium hydroxide = Ca(OH)2 Ca = 1 atom OH = 2 atoms
44 moles of atoms
The chemical formula (not symbol) of calcium bicarbonate is Ca(HCO3)2.
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Ca(HCO3)2
The Valency of Bicarbonate is - 1. Therefore: Calcium + Bicarbonate = Ca(HCO3)2 as Calcium is 2 and Bicarbonate is -1 Similarly Zn + HCO3 = Zn(HCO3)2 Na + HCO3 = NaHCO3
In 3Ca(OH)2 there are three Ca(OH)2 - (Calcium hydroxide) moleculesIn one Ca(OH)2 there is one Calcium, and two (OH) units. In one (OH) unit there is one Oxygen and one Hydrogen. With the above information it evident that there are 5 atoms in one Ca(OH)2 molecule and as there are 3 of these molecules present, there would be a total of 15 atoms present in 3Ca(OH)2
Formula: Ca(HCO3)2
Ca(HCO3)2
The formula is not charge balanced. Meaning the Ca has a 2+ charge and the HCO3 has a net 1- charge. Thus, the formula is incorrect. If you remove the Hydrogen you make CO3 a 2- charged anion giving you CaHCO3 (Calcuim carbonate), or the Ca can bond with two HCO3 (hydrogen carbonate) anions to form Ca(HCO3)2 (Calcium bicarbonate)
1.34 moles Ca x 6.02x10^23 atoms Ca/mole Ca = 8.07x10^23 atoms of Ca
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For plutonium 239: ca. 74,68.1023 atoms