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What mass of tungsten is present in 10lbs of FeWO4?
To determine the mass of tungsten in 10 lbs of FeWO4, we first need to calculate the molar mass of FeWO4 (iron(II) tungstate). FeWO4 has a molar mass of approximately 303.85 g/mol. Next, we convert 10 lbs to grams (10 lbs = 4535.92 g) and determine the moles of FeWO4 present. Finally, we use the molar ratio of tungsten to FeWO4 (1:1) to calculate the mass of tungsten present, which is equal to the molar mass of tungsten (183.84 g/mol). The mass of tungsten in 10 lbs of FeWO4 is approximately 1838.4 g.
How many atoms are in 1.85 moles of Fe?
One mole of any mono-atomic element contains (by definition) 6.022*10+23 atoms. please calculate from there by multiplying - 11,14.1023 atoms.
How many atoms in iron oxide Fe2O3?
There are 6 atoms of oxygen represented by this.
How many atoms are in 3Fe(OH)3?
There are a total of 13 atoms in 3Fe(OH)3. This includes 3 iron (Fe) atoms, 9 oxygen (O) atoms, and 3 hydrogen (H) atoms.
How many atoms are in the formula 3 Fe2O3?
15 Fe2O3 has 2 + 3 atoms = 5 atoms Multiply the whole thing by 3 and you end up with 15 atoms.
How many atoms are present in 4.80 mole of Fe?
4,80 moles of Fe contain 28,9062761136.10e23 atoms.
How many atoms are in 2 Fe squared?
9
How many atoms does Fe3O4 have?
Fe3O4 has a total of 7 atoms, with 3 iron atoms (Fe) and 4 oxygen atoms (O).
How many atoms are in Fe(NO3)2?
newdiv
How many atoms does iron filings have?
It depends on the mass of iron. 1 mole Fe = 55.845g = 6.022 x 1023 atoms Fe
What mass of tungsten is present in 10lbs of FeWO4?
To determine the mass of tungsten in 10 lbs of FeWO4, we first need to calculate the molar mass of FeWO4 (iron(II) tungstate). FeWO4 has a molar mass of approximately 303.85 g/mol. Next, we convert 10 lbs to grams (10 lbs = 4535.92 g) and determine the moles of FeWO4 present. Finally, we use the molar ratio of tungsten to FeWO4 (1:1) to calculate the mass of tungsten present, which is equal to the molar mass of tungsten (183.84 g/mol). The mass of tungsten in 10 lbs of FeWO4 is approximately 1838.4 g.
How many atoms are present in 400g Iron?
1 mole Fe = 6.022 x 1023 atoms Fe1 mole Fe = 55.845g Fe (atomic weight in grams)Convert grams Fe to moles Fe.400g Fe x (1mol Fe/55.845g Fe) = 7.16mol FeConvert moles Fe to atoms Fe.7.16mol Fe x (6.022 x 1023atoms Fe/1mol Fe) = 4.31 x 1024 atoms Fe
How many atoms are in fe2O2?
There are 4 atoms in Fe2O2: 2 atoms of iron (Fe) and 2 atoms of oxygen (O).
How many atoms are in Fe2O4?
There are 10 atoms in Fe2O4 - 2 iron (Fe) atoms and 8 oxygen (O) atoms.
How many atoms are there in 1 cm3 of iron?
The density of iron, Fe, at room temperature is 7.874 g/cm3. So 1cm3 of iron has a mass of 7.874g. 1 mole iron = 55.845g Fe = 6.022 x 1023 atoms Fe. 7.874g Fe x 6.022 x 1023 atoms Fe/55.845g Fe = 8.491 x 1022 atoms Fe
What number of Fe atoms and what amount of Fe atoms are in 500 g of Fe?
Known/Given:1 mole of Fe = 55.845g Fe (its atomic weight in grams)1 mole of Fe = 6.022 x 1023 atoms Fe (from Avogadro's number)Convert grams Fe to moles Fe.600.0g Fe x 1mol Fe/55.845g Fe = 10.74mol FeConvert moles Fe to atoms Fe.10.74mol Fe x 6.022 x 1023atoms Fe/1mol Fe = 6.468 x 1024atoms Fe
How many atoms are present in 4.80 moles of Fe?
To find the number of atoms in 4.80 moles of Fe, you need to use Avogadro's number, which is 6.022 x 10^23 atoms/mol. So, 4.80 moles of Fe would contain: 4.80 moles x 6.022 x 10^23 atoms/mol = 2.89 x 10^24 atoms of Fe.
