Iron(II) tungstate, FeWO4, is an ionic compound which means that the smallest particle is a formula unit. One formula unit of FeWO4 has one Fe^2+ ion.
To determine the mass of tungsten in 10 lbs of FeWO4, we first need to calculate the molar mass of FeWO4 (iron(II) tungstate). FeWO4 has a molar mass of approximately 303.85 g/mol. Next, we convert 10 lbs to grams (10 lbs = 4535.92 g) and determine the moles of FeWO4 present. Finally, we use the molar ratio of tungsten to FeWO4 (1:1) to calculate the mass of tungsten present, which is equal to the molar mass of tungsten (183.84 g/mol). The mass of tungsten in 10 lbs of FeWO4 is approximately 1838.4 g.
One mole of any mono-atomic element contains (by definition) 6.022*10+23 atoms. please calculate from there by multiplying - 11,14.1023 atoms.
There are 6 atoms of oxygen represented by this.
There are a total of 13 atoms in 3Fe(OH)3. This includes 3 iron (Fe) atoms, 9 oxygen (O) atoms, and 3 hydrogen (H) atoms.
15 Fe2O3 has 2 + 3 atoms = 5 atoms Multiply the whole thing by 3 and you end up with 15 atoms.
4,80 moles of Fe contain 28,9062761136.10e23 atoms.
9
Fe3O4 has a total of 7 atoms, with 3 iron atoms (Fe) and 4 oxygen atoms (O).
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It depends on the mass of iron. 1 mole Fe = 55.845g = 6.022 x 1023 atoms Fe
To determine the mass of tungsten in 10 lbs of FeWO4, we first need to calculate the molar mass of FeWO4 (iron(II) tungstate). FeWO4 has a molar mass of approximately 303.85 g/mol. Next, we convert 10 lbs to grams (10 lbs = 4535.92 g) and determine the moles of FeWO4 present. Finally, we use the molar ratio of tungsten to FeWO4 (1:1) to calculate the mass of tungsten present, which is equal to the molar mass of tungsten (183.84 g/mol). The mass of tungsten in 10 lbs of FeWO4 is approximately 1838.4 g.
1 mole Fe = 6.022 x 1023 atoms Fe1 mole Fe = 55.845g Fe (atomic weight in grams)Convert grams Fe to moles Fe.400g Fe x (1mol Fe/55.845g Fe) = 7.16mol FeConvert moles Fe to atoms Fe.7.16mol Fe x (6.022 x 1023atoms Fe/1mol Fe) = 4.31 x 1024 atoms Fe
There are 4 atoms in Fe2O2: 2 atoms of iron (Fe) and 2 atoms of oxygen (O).
There are 10 atoms in Fe2O4 - 2 iron (Fe) atoms and 8 oxygen (O) atoms.
The density of iron, Fe, at room temperature is 7.874 g/cm3. So 1cm3 of iron has a mass of 7.874g. 1 mole iron = 55.845g Fe = 6.022 x 1023 atoms Fe. 7.874g Fe x 6.022 x 1023 atoms Fe/55.845g Fe = 8.491 x 1022 atoms Fe
Known/Given:1 mole of Fe = 55.845g Fe (its atomic weight in grams)1 mole of Fe = 6.022 x 1023 atoms Fe (from Avogadro's number)Convert grams Fe to moles Fe.600.0g Fe x 1mol Fe/55.845g Fe = 10.74mol FeConvert moles Fe to atoms Fe.10.74mol Fe x 6.022 x 1023atoms Fe/1mol Fe = 6.468 x 1024atoms Fe
To find the number of atoms in 4.80 moles of Fe, you need to use Avogadro's number, which is 6.022 x 10^23 atoms/mol. So, 4.80 moles of Fe would contain: 4.80 moles x 6.022 x 10^23 atoms/mol = 2.89 x 10^24 atoms of Fe.