1 mole NCl3 = 120.366g NCl3 = 6.022 x 1023 molecules NCl3
8.2 x 1022 molecules NCl3 x 120.366g NCl3/6.022 x 1023 molecules NCl3 = 16g NCl3 rounded to 2 significant figures
To find the grams of nitrogen dioxide needed, first calculate the moles of nitrogen monoxide using Avogadro's number. Then, use the balanced chemical equation to determine the moles of nitrogen dioxide required. Finally, convert moles to grams using the molar mass of nitrogen dioxide.
The mass of the Earth's atmosphere is 5.25x10^21 grams. If we assume the molar mass of air is approximately 29 grams per mole we get:(5.25x10^21) multiplied by Avogadro's constant (6.02x10^23) and then divided by (29 grams/ mol) = 1.09x10^44 molecules of air in the atmosphere.
There are approximately 0.5 moles of NaCl in 29.22 grams. This would be 3.01 x 10^23 molecules of NaCl.
> Hydrogen chloride = HCl Nitrogen has many oxides : > Dinitrogen monoxide = N2O > Nitrogen monoxide = NO > Dinitrogen trioxide = N2O3 > Nitrogen dioxide = NO2 > Dinitrogen tetroxide = N2O4 > Dinitrogen pentoxide = N2O5
To find the number of atoms in 1.3 x 10^22 molecules of NO2, we need to consider the number of atoms in each molecule. NO2 has 3 atoms (1 nitrogen and 2 oxygen). So, the total number of atoms in 1.3 x 10^22 molecules of NO2 would be 3.9 x 10^22 atoms.
The nitrogen iodide is NI3.
To calculate the number of grams in 4.1 x 10^22 molecules of N2I6, you first need to find the molar mass of N2I6. Then, use this molar mass to convert the number of molecules to grams using Avogadro's number and the formula: grams = (number of molecules) / (Avogadro's number) * molar mass.
To find the mass, we divide by Avogadro's number to find the amount of moles. We then multiply the moles by the molar mass of the compound which is 60.08 grams. Doing all of this, we get a mass in grams of 5.59 grams.
To find the grams of nitrogen dioxide needed, first calculate the moles of nitrogen monoxide using Avogadro's number. Then, use the balanced chemical equation to determine the moles of nitrogen dioxide required. Finally, convert moles to grams using the molar mass of nitrogen dioxide.
To find the number of molecules in 2.16 moles of NCl3, you can use Avogadro's number, which is 6.022 x 10^23 molecules/mol. Multiply 2.16 moles by Avogadro's number to get 1.3 x 10^24 molecules of NCl3.
The first step is calculating how many molecules of glucose are in 3.00 grams. To do this, you need the molecular mass of the compound (glucose), which is found by adding up the weights of the elements involved in C6H12O6. C6: 12.0 × 6 = 72.0 H12: 1.0 × 12 = 12.0 O6: 16.0 × 6 = 96.0 72.0 + 12.0 + 96.0 = 180.0 grams/mol With this and Avogadro's constant (6.02 × 1023), we can then convert 3.00 grams of glucose to number of molecules. 3.00 grams ÷ 180.0 grams/mol × (6.02 × 1023) = 1.00 × 1022 molecules of glucose So now we know how many molecules of glucose there are. We also know from the formula that in one molecule of glucose, there are 6 atoms of carbon, 12 atoms of hydrogen, and 6 atoms of oxygen. Number of atoms in one molecule × number of molecules = number of atoms in given amount 6 × (1.00 × 1022) = 6.00 × 1022 atoms of carbon 12 × (1.00 × 1022) = 1.20 × 1023 atoms of hydrogen 6 × (1.00 × 1022) = 6.00 × 1022 atoms of oxygen
1.814*1022
The mass is 2.86 grams but the weight will be 0.028 Newtons.
2.50 grams C14H18N2O5 (1 mole C14H18N2O5/294.304 grams)(18 moles H/1 mole C14H18N2O5)(6.022 X 1023/1 mole H) = 9.21 X 1022 atoms of aspartame
Avogadro's Number is defined as the number of molecules in one gram atomic molecular mass of a substance and is known to have the approximate value of 6.022 X 1023. The gram molecular mass of water, with formula H2O, is 18.01528. Therefore, the number of water molecules in 1.805 grams of water is: (1.805/18.01528)(6.022)(1023) or 6.034 X 1022 molecules, to the justified number of significant digits.
To find the mass, we divide by Avogadro's number to find the amount of moles. We then multiply the moles by the molar mass of the compound which is 60.08 grams. Doing all of this, we get a mass in grams of 5.59 grams.
25 grams / (17 grams/mole) x 6.022x1023 molecules/mole = 8.9x1023 molecules