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The key is to understand that Mg is limiting. Therefore, the final number of moles of H2 will equal the starting number of moles of Mg. Using gas law equations we can first find the moles of H2 and then find the moles of Mg. 1. PV = nRT --> n = PV/RT P = 760 mm Hg (pressure at STP) V = 80.0 mL (given) R = 62,400 mL-mm Hg/mol-K (constant) T = 273 K (temp. at STP) Now you have all the information you need to solve for the number of moles of Mg. Solve for moles and convert to grams.

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15y ago
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Q: How many grams of Mg must react with HCl in order to produce 80 mL of hydrogen gas at STP?
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