Approx 2.7836
To double the volume of the balloon, you would need to add an additional 8.00 g of helium gas. This is because the ideal gas law states that the volume of a gas is directly proportional to the amount of gas present, assuming constant temperature and pressure. So, if you double the amount of gas, you double the volume of the balloon.
No, nitrous oxide has a density of around 1.977 grams/liter, "air" at sea level has a density of 1.2 grams/liter, meaning that nitrous oxide is more dense than air. Helium on the other hand has a density of 0.1785 grams/liter, making it less dense than air... Also making helium a popular choice for filling balloons. Hydrogen is another common balloon filling gas. Although it is highly flammable. (Hindenburg)
The weight of a balloon can vary depending on its size, material, and contents. A standard latex balloon filled with helium typically weighs around 14 grams, while a larger foil balloon filled with helium can weigh around 20 grams. However, if the balloon is filled with air instead of helium, its weight will be significantly higher due to the denser nature of air.
helium = 4 molar mass
To find the number of helium atoms in the blimp, you first calculate the number of moles of helium in 533 kg of helium using the molar mass of helium. Then, you use Avogadro's number (6.022 x 10^23) to convert moles to atoms. The final answer will give you the number of helium atoms in the blimp.
depends how big the helium balloon is and how many
To double the volume of the balloon, you would need to add an additional 8.00 g of helium gas. This is because the ideal gas law states that the volume of a gas is directly proportional to the amount of gas present, assuming constant temperature and pressure. So, if you double the amount of gas, you double the volume of the balloon.
16 grams of oxygen, O2, is 0.5 mole, 2 grams of helium, He, is also 0.5 mole. They therefore contain the same number of gas "particles" (molecules for O2, atoms for He) and they will have almost identical volumes at the same pressure
0.54 grams 1 mol = mass / Mr = mass / 4 (Helium's atomic weight is 4, it is a monoatomic gas) 1 mol = 0.54 / 4 = 0.00135 # of molecules of helium in the balloon = 0.00135 * 6.02 * 10^23
* Calculate the volume of the ballon * Calculate the weight of the helium: G= V x 0,1786 (the helium density in g/L) * Add the weight of the balloon material (rubber, plastic, etc.)
To find the mass of helium in the balloon, you need to use the ideal gas law equation: PV = nRT. First, find the number of moles of helium using PV = nRT, and then convert moles to grams using the molar mass of helium (4.00 g/mol). Finally, you can calculate the mass of helium in the balloon.
To calculate the amount of helium in the balloon, we need to convert the mass of helium gas to moles using the molar mass of helium. The molar mass of helium is 4 g/mol. So, 0.54 grams of helium is equal to 0.54/4 = 0.135 moles of helium. Finally, we can use Avogadro's principle to convert moles to the number of helium atoms present in the balloon.
The weight of the helium gas inside the balloon can be calculated using its molar mass, the Ideal Gas Law, and the given volume. Assuming standard conditions, helium gas has a molar mass of 4 grams per mole. Thus, a 22.4 liter balloon filled with helium gas would weigh approximately 32 grams.
A standard 11-inch helium balloon can lift approximately 14 grams or 0.5 ounces. The lifting capacity of a helium balloon can vary depending on factors such as balloon size, helium volume, and weight of the attached object.
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A helium balloon can typically lift a few grams of weight, which is equivalent to only a few sheets of paper. The exact number of pieces of paper it can pick up would depend on the weight and size of the paper.
The weight of an inflated balloon can vary depending on the size and material of the balloon. On average, a standard latex balloon filled with air weighs less than a gram, while a larger helium-filled foil balloon can weigh a few grams to a few ounces.