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How many grams of iron can be obtained from a 268g sample of iron 3 oxide?
Wiki User
∙ 15y ago
Iron (III) oxide -> Iron + Oxygen
Steps to find the mass of iron obtained from 268g of iron (III) oxide:
Step 1: Write the balanced equation
2Fe2O3 -> 4Fe + 3O2
Step 2: Identify key reactants and products
2Fe2O3 -> 4Fe
Step 3: Write down the mole ratio
2 moles : 4 moles
Step 4: Change moles into gram formula mass
2((2x56)+(3x16)) : 4(1x56)
320g : 224g
Step 5: Find out how many grams of iron will be produced for every gram of iron (III) oxide
1 gram = 224/320 = 0.7g
Step 6: Find out how many grams of iron will be produced for 268 grams of iron (III) oxide
268 grams = (224/320)x268 = 187.6 grams
The mass of iron produced from 268 grams of iron (III) oxide is 187.6 grams.
Wiki User
∙ 15y ago
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How many ounces in 268g?
That is 9.453 ounces.
How many atoms of He gas are found in 0.268 g. the molar mass of He. the moles of He. the number of atoms of He gas .?
There is apporximately 0.07 mol of He in .268g, which is approximately 4.21x10^-23 atoms.
What is Dubnuim?
Dubnium is an element with atomic number 105. marked as Db. Atomic weight (of stable isotop)-268g D-Block Element-Period 7 & group 5. Properties similar to that of other members in group 5. Dubnium is not present in nature but belongs to those elements prepared synthetically in labs. First observed in Russia.
