help me on this quisdtoin
The chemical formula for potassium nitrate dissolved in water is KNO3(aq), which shows that potassium nitrate has dissociated into its constituent ions (K+ and NO3-) in the water solution.
65 degrees of potassium nitrate will remain in water while only 35% of water will still be detectable in the solute potassium nitrate
Potassium nitrate is soluble in water, as it is an ionic solid. When dissolved in water, potassium nitrate will form an aqueous solution of potassium and nitrate ions.
As the KNO3 solution cools, solubility of KNO3 decreases with temperature, leading to the formation of excess KNO3 crystals. These crystals will start to precipitate out of the solution as it cools. If the cooling continues, more crystals will form until the solution becomes saturated at a lower temperature.
KNO3 has 3 elements which are potassium, Nitrogen and Oxygen.
Instead of waiting for the answer, I ended up solving it. lol 300grams of H20 X 110grams of KNO3/100 grams of H20 = 330 grams of KNO3 The grams of H20 both cancel out and leave you with 330 grams of KNO3 Containing the solubility of KNO3. At 60 degrees celsius the KNO3 grams were 110, which is (over) / 100grams of H20. Hope this helps with this workbook problem :)
Potassium nitrate is a solid at 60 oC.
To determine if a solution is saturated or unsaturated, we need to compare the actual solubility of the solute at the given temperature to the amount of solute dissolved in the solution. At 40 degrees Celsius, the solubility of KNO3 in water is approximately 80 g/100 g water. Since you have 110 g of KNO3 in 100 g of water, the solution is supersaturated because it contains more solute than it can normally hold at that temperature.
The solubility of KNO3 in water is limited by its equilibrium solubility product. Once this limit is reached, no more KNO3 can dissolve at that temperature. In this case, the solubility of KNO3 at 20°C in water is about 37 grams per 100 ml of water, which means the solution is saturated and cannot hold more KNO3 in a dissolved state without exceeding that limit.
Get moles by; Molarity = moles of solute/Liters of solution 0.50 M KNO3 = moles KNO3/2.0 L = 1.0 mole KNO3 Now find grams of 1.0 mole KNO3 1.0 mole KNO3 (101.11 grams/1 mole KNO3) = 101.11 grams KNO3 needed call it 100 grams
Between 1 and 2 kg/L KNO3 at 600C would be a good guess. This is based on rough data found in en.wikipedia: 133 g/L (0 °C) 383 g/L (25 °C) 2470 g/L (100 °C)
potassium nitrate solubility at room temperature 25 degree celsius is about 383 g /L.if we want per 100 ml then .... 383 g / 1000ml ....we know that1 L=1000mlnow for per 100 ml it becomes38.3g/100mlnow we can see that KNO3 solubility in 100 ml solution is 38.3 g.....so we can say that100 ml solution of KNO3 can not hold more than 37 g or 38.3 g of KNO3 in dissolved state.
Read a text book
The solubility of KNO3 in water is limited by the solubility product constant, which is the equilibrium constant for dissolution of the salt in water. If more than 37g of KNO3 is added to 100ml of solution, it exceeds the maximum amount that can be dissolved at that temperature, leading to the excess forming a separate solid phase.
The molecular weight of potassium nitrate (KNO3) is 101.1 grams/mole.K = 39.1 + N = 14.0 + O = 3*16.0 = 101.1Now divide 6.5 by 101.1 to calculate # of moles => 0.064 moles KNO3
The chemical symbol for potassium nitrate is potassium. "KNO3"
When KNO3 is dissolved in water, it absorbs heat from the surroundings, causing the temperature of the solution to decrease. This is an endothermic process, meaning it requires energy, which it takes from the surroundings. As a result, the test tube and the water around it feel cold as heat is transferred to the KNO3 solution.