The molar mass of water(H2O)=18((1*2)+16)
The no. of moles(n) of water in 18 g of water=mass/molar mass=18 g/ 18 g mol-1 =1 mol
The no. of molecules of water in 18 of water=n*Avogadro no. =1 mol*6.022*1023 mol-1 =6.022*1023
The no. of atoms of oxygen in one mole of water=1 mol
The no. of atoms of oxygen in 6.022*1023mol of water= 6.022*1023
First find the percentage by mass of oxygen in water. The formula for water is H2O, showing that water contains two hydrogen atoms for every atom of oxygen. The gram atomic masses of hydrogen and oxygen are 1.00794 and 15.9994 respectively. Therefore, the percentage of oxygen in water is 100{15.9994/[15.9994 + 2(1.00794)]} or about 88.8 %, to the justified number of significant digits; the ratio of the maximum mass of water that can be made from a given mass of oxygen is 1/0.888 or about 1.126; and the answer to the question is this number multiplied by the stated mass of oxygen, or 24.9 grams, to the justified number of significant digits.
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
To calculate the number of grams of oxygen needed to react with 6.78 grams of ammonia, we first write out the balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) to form nitrogen monoxide (NO) and water (H2O). Then we use the stoichiometry of the equation to find the molar ratio between ammonia and oxygen. Finally, we convert the mass of ammonia to moles and then use the molar ratio to find the mass of oxygen needed.
11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.
Oxygen makes up about 46.6% of the Earth's crust by weight. The approximate total mass of the Earth's crust is around 2.7 x 10^22 grams. Therefore, you can calculate the grams of oxygen in the Earth's crust by multiplying these two percentages.
There are 424 grams of oxygen in 477 grams of water. 8 times 53 equals 424.
how many grams are contained in 11.89 pounds?
1 mol of oxygen is 16.00g. Therefore 2.43g of oxygen would contain 0.152 mols of oxygen. (2.43g/16.00g)
I believe you would divide the kg by 88.8 to get 1%, then multiply by 100 to get the total mass. If you want it in grams then multiply by 1000. The answer ends up as 2759 grams. Feel free to correct me if you think I am wrong.
3,45 grams of H2O contain 1,154.10e23 oxygen atoms.
67.5 grams of H2O
25.78g
25
The answer is 165,5 g water.
To find the grams in 0.644 mol of oxygen, you need to multiply the number of moles by the molar mass of oxygen. The molar mass of oxygen is approximately 16 g/mol. Therefore, 0.644 mol of oxygen would contain 0.644 mol x 16 g/mol = 10.304 grams of oxygen.
9394.1 grams
5,393.213 grams.