96,27 g of sand contain 45 g of silicon (if the sand is pure silicon dioxide).
Si + 2Cl2 --> SiCl4 24.4 grams silicon (1 mole Si/28.09 grams)(2 mole Cl2/1 mole Si)(70.9 grams/1 mole Cl2) = 123 grams chlorine needed =====================
6.02
70
89.3
0.50 grams of BeCl2
Si + 2Cl2 --> SiCl4 24.4 grams silicon (1 mole Si/28.09 grams)(2 mole Cl2/1 mole Si)(70.9 grams/1 mole Cl2) = 123 grams chlorine needed =====================
6.02
A US pint is 473 grams. - An Imperial pint is 568 grams
70
89.3
89.3
Four and half
Sodium sulfate is not prepared from hydrogen chloride.
0.50 grams of BeCl2
The answer is 7,5g.
1.47g
HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.