Stoichiometrically:
2 Al :=: 3 H2SO4 :=: 1 Al2(SO4)3
Molarity: 2:3:1
15 Al :=: 22.5 mole H2SO4 :=: 7.5 moles Al-sulfate
It's a long time since I did chemistry, but I'd like a shot at this one. The reaction would be something like: 2(Al) + 3(H2SO4) = Al(2)(SO4)3 + 3(H2).
Aluminium has a valency of 3 (I seem to remember) and the sulphate ion has a valency 2. Therefore two Als and three SO4s make a molecule with six covalent bonds -- Aluminium Sulphate.
Hydrogen gas is a cloud of H2 molecules so we have two moles of Aluminium making three moles of hydrogen gas. 3 moles of aluminium therefore make 3x3/2 = 4.5 moles of hydrogen gas. Now, a mole of gas at STP has a volume of 22.4 litres. So the answer is 4.5 x 22.4 litres by volume. That is 100.8 litres.
27 moles or 54 g of Hydrogen gas will produce.
2Al + 3H2SO4 ------> Al2(SO4)3 + 3H2 ,
2 moles of Al produce 3 moles of H2
1 mole --------------------3/2 moles
18 moles------------------3/2 x 18 = 27 moles
Wanna know how to make $10k per month while you sleep? Click the link in my bio I'm shocked at the results 😳
Aluminium sulfide is Al2S3 and there is no hydrogen in it.
8,0 moles of aluminum sulfate contain 23,955 moles sulfur.
The volume is 22,98 L.
0.1693 mol
Hydrogen Sulfide has a total of three atoms. Hydrogen has two, and Sulfur has one. H2S.
The formula for ammonium sulfide is (NH4)2S. Therefore, each formula unit contains 8 hydrogen atoms.
Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
I am not sure of the work but, i know the answer is 8.9 X 10^23 atoms Al.
1.64 x 1025
Hydrogen Sulfide has a total of three atoms. Hydrogen has two, and Sulfur has one. H2S.
there are 1.30e25 Hydrogen atoms in 2.70 mol Ammonium Sulfide
there are 1.30e25 Hydrogen atoms in 2.70 mol Ammonium Sulfide
338.10e23 hydrogen atoms
Each molecule of hydrogen sulfide contains two hydrogen atoms and one sulfur atom.
The answer is 175,08.10e23 atoms.
The answer is 1,72.10e25 atoms.
1
4,2.10e25 H atoms
The formula for ammonium sulfide is (NH4)2S. Therefore, each formula unit contains 8 hydrogen atoms.
Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
I am not sure of the work but, i know the answer is 8.9 X 10^23 atoms Al.