0
What else can I help you with?
How many moles of NaCl would form from 3.25 moles of NaHCO3?
To find the moles of NaCl formed from NaHCO3, we need to consider the stoichiometry of the reaction. The balanced equation is: 2 NaHCO3 -> Na2CO3 + H2O + CO2 Therefore, for every 2 moles of NaHCO3, we get 1 mole of NaCl. Therefore, 3.25 moles of NaHCO3 would produce 1.625 moles of NaCl.
If a typical antacid tablet contains 2 grams of sodium hydrogen carbonate how many moles of carbon dioxide should one tablet yield?
NaHCO3 = 84.007 g/mol Figure out the mole fraction = 2g / 84.007 g/mol The unit of the answer is mol, which in this context is the same as mole. Since you only have one carbon in NaHCO3 you cannot have more moles of CO2 than moles of NaHCO3.
What is the balanced equation for hno3 plus nahco3-nano3 plus H2O plus CO2?
The balanced equation for the reaction between HNO3 and NaHCO3 is: 2 HNO3 + NaHCO3 → NaNO3 + H2O + CO2
Chemical formula for sodium hydrogencarbonate?
The answer is NaHCO3
If 2.10 g of NaHCO3 are decomposed then how many grams of water are produced?
NaHCO3 ----> H2O Mass 2.10g 0.045g RAM 84 g/moles 18 g/moles number of moles 0.025moles 0.025moles
How many moles of NaCl would form from 3.25 moles of NaHCO3?
To find the moles of NaCl formed from NaHCO3, we need to consider the stoichiometry of the reaction. The balanced equation is: 2 NaHCO3 -> Na2CO3 + H2O + CO2 Therefore, for every 2 moles of NaHCO3, we get 1 mole of NaCl. Therefore, 3.25 moles of NaHCO3 would produce 1.625 moles of NaCl.
How many moles of NaHCO3 are present in a 6.10 g sample?
Divide 6.10 (g NaHCO3) by 84.007 (g.mol−1 NaHCO3) to get 0.0726 mol NaHCO3
If a typical antacid tablet contains 2 grams of sodium hydrogen carbonate how many moles of carbon dioxide should one tablet yield?
NaHCO3 = 84.007 g/mol Figure out the mole fraction = 2g / 84.007 g/mol The unit of the answer is mol, which in this context is the same as mole. Since you only have one carbon in NaHCO3 you cannot have more moles of CO2 than moles of NaHCO3.
What is the balanced equation for hno3 plus nahco3-nano3 plus H2O plus CO2?
The balanced equation for the reaction between HNO3 and NaHCO3 is: 2 HNO3 + NaHCO3 → NaNO3 + H2O + CO2
How many moles are in 2.10 kg of NaHCO3?
For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams110 grams NaHCO3 / (84.0 grams) = 1.31 moles NaHCO3
Chemical name for sodium bicarbonate?
Sodium bicarbonate is not an element. It is a compound of 4 elements. As to the name, it's sodium bicarbonate or sodium hydrogen carbonate. The formula is NaHCO3
Chemical formula for sodium hydrogencarbonate?
The answer is NaHCO3
How many moles of NaHCO3 are present in 3.00 g sample?
To find the moles of NaHCO3 in a 3.00 g sample, first calculate the molar mass of NaHCO3 (84.01 g/mol). Then, divide the mass of the sample by the molar mass to obtain the moles of NaHCO3. For this sample, 3.00 g / 84.01 g/mol ≈ 0.036 moles of NaHCO3 are present.
What is the ratio of NaHCO3?
The ratio of NaHCO3 to WHAT!
Why is 2-naphthol insoluble in NaHCO3?
2-naphthol is insoluble in NaHCO3 because it is a weak acid and can only partially ionize in solution. Therefore, it does not interact strongly with the bicarbonate ions in NaHCO3 to form a soluble salt.
What mass of NaHCO3 is needed to neutralize 150ml of 044M HCl?
Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer
If 2.10 g of NaHCO3 are decomposed then how many grams of water are produced?
NaHCO3 ----> H2O Mass 2.10g 0.045g RAM 84 g/moles 18 g/moles number of moles 0.025moles 0.025moles
