How many joules of energy are required to raise the temperature of 65 grams of iron from 25 degrees celsius to 95 degrees celcsius?

Answer 1

The specific heat of iron is either 0.46 or 0.45 Jolules/grams*Celsius, so.........

q(in Joules) = mass * specific heat * Temp final - Temp. initial

q = (65 grams Fe)(0.46 J/gC)(95 C - 25 C)

= 2093 joules of energy

Answer 2

Specific heat of iron is 0.46 J/gC so, use;

q = mass * specific heat * change in temp.

q = (35 g Fe)(0.46 J/gC)(35 C - 25 C)

= 161 Joules (1 calorie/4.184 Joules)

= 38 calories

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Answer 3

The specific heat capacity of iron is 0.449 J/g°C. Using the formula Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change, we can calculate the energy required. Q = 65g * 0.449 J/g°C * (95°C - 25°C) = 1966.25 Joules.

Answer 4

The formula is: 0,108 x 3000 x (T1 -T2), in kilocalories.

Answer 5

heat = 3000 g x 0.450 J/g/deg x 5 deg = 6,750 Joules or 6.75 kJoules