Molecular mass of AlCl3 = 27.0 + 3(35.5) = 133.5
Amount of AlCl3 = 400/133.5 = 3.00mol
The ratio of Cl to AlCl3 is 3:1.
Amount of Cl = 3 x 3.00 = 9.00mol
In 1 mol of AlCl3, there are 3 chloride ions. First calculate the moles of AlCl3 in the solution: 65.5 mL is 0.0655 L. Multiply 0.0655 L by 0.210 mol/L to get the moles of AlCl3. Finally, multiply this by 3 to find the number of chloride ions in the solution.
The amount of energy released when one mole of chloride ions is produced from one mole of chlorine atoms is the electron affinity of chlorine. This is the energy change that occurs when an electron is added to a chlorine atom to form a chloride ion.
There are approximately 1.97 moles of chlorine in 70g. This is calculated by dividing the mass of the sample by the molar mass of chlorine (approximately 35.5 g/mol).
602200000000000000000000 atoms or 6.022 X 10^23
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 1.5 moles Na+ and 1.5 moles Cl-, totaling 3 moles of ions altogether
1 mole of AlCl3 will dissociate into 4 moles of ions in aqueous solution: 1 mole of Al+3 ions and 3 moles of Cl- ions.
10 grams of AlCl3 contains a certain number of moles in particles.1 mole of AlCl3 weighs (26.9815386+(3*35.453)=133.3405386), let's round that to 133.3405 grams.So 10 grams = 10/133.3405 = 0.075 mole of AlCl3 (rounded), but for each AlCl3 we have, you get 4 ions (1 Al3+, 3Cl-). So we have 0.075 moles, but we get 4 times as many ions. 0.075*4=0.3 mole1 mole = 6.022141x1023 (Avogadro's Number)0.3 mole = 1.81x1023 ions
In 1 mol of AlCl3, there are 3 chloride ions. First calculate the moles of AlCl3 in the solution: 65.5 mL is 0.0655 L. Multiply 0.0655 L by 0.210 mol/L to get the moles of AlCl3. Finally, multiply this by 3 to find the number of chloride ions in the solution.
0.355 M AlCl3 (3 moles Cl/1 mole AlCl3)= 1.07 M Cl================Naturally.0.355 M Al============add1.43 M total=========
The amount of energy released when one mole of chloride ions is produced from one mole of chlorine atoms is the electron affinity of chlorine. This is the energy change that occurs when an electron is added to a chlorine atom to form a chloride ion.
The lattice energy of AlCl3 is the energy released when one mole of the compound is formed from its constituent ions in the solid state. A higher lattice energy indicates a stronger bond between the ions, leading to greater stability of the compound. In the case of AlCl3, its high lattice energy contributes to its overall stability.
Balanced equation: 2Al + 3Cl2 -> 2AlCl3For every 3 moles of Cl2, 2 moles of AlCl3 is produced (Using the numbers in front of the compounds)Now set up a proportion: 3/2 = 0.30/?Cross Multiply: (2 X 0.30) / 3 = 0.20.2 moles of AlCl3 will be produced.
The simplest formula for the compound formed by 0.200 mole of aluminum (Al) and 0.600 mole of chlorine (Cl) is AlCl3, which is aluminum chloride. The ratio of Al to Cl in the compound is 1:3, leading to the formula AlCl3.
There is one mole of Na⁺ ions for every mole of NaCl. This is because each mole of NaCl dissociates into one mole of Na⁺ ions and one mole of Cl⁻ ions in solution.
There are 1 mole of sodium ions in 1 mole of NaCl, as there is one sodium ion for each chlorine ion in the compound. Therefore, in 2 moles of NaCl, there are 2 moles of sodium ions, which is equal to 2 x 6.022 x 10^23 sodium ions.
A mole of calcium has 6.022 X 1023 calcium ions.
When HCl dissociates, it produces 1 mole of H+ ions and 1 mole of Cl- ions for every mole of HCl. So, 1 mole of HCl will produce a total of 2 moles of ions (H+ and Cl-).