How many molecules are present in 13.77lb of magnesium bromide?

Answer 1

? molc' MgBr2 = (13.77lbs)(453.59g/1lbs)(1 mol/184.11g)(6.02e23 molc'/1 mol) 13.77 lbs =2.04e25 molecules

Answer 2

To calculate the number of molecules in 13.77 lb of magnesium bromide, we first need to convert the weight to grams. Then, we can use the molar mass of magnesium bromide to find the number of moles. Finally, we can use Avogadro's number (6.022 x 10^23) to determine the number of molecules.