2.75 x 1024molecules of CO2
The reaction is :- 2C2H6 + 7O2 ----------> 4CO2 + 6H2O When one mole ethane is combusted 7/2 moles of oxygen are used. When 3 moles of ethane are combusted 3 x 7/2 moles of oxygen used. No. of oxygen molecules consumed =6.022 x 1023 x7/2= 21.077 x 1023=2.107 x 1024 molecules.
In the reaction 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(l), the entropy decreases. This is because the reactants consist of gaseous molecules, which have higher entropy due to their greater freedom of movement, while the products include liquid water, which has lower entropy. Additionally, there is a reduction in the number of gas molecules from 7 (2 C2H2 + 5 O2) to 4 (4 CO2), further contributing to the decrease in disorder. Overall, the transition from gas to liquid and the reduction in the number of gas molecules results in a net decrease in entropy.
2C2H6 + 7O2 --> 4CO2 + 6H2O
The chemical reaction when C2H6 gas (ethane) is combusted is: 2C2H6 + 7O2 -> 4CO2 + 6H2O. Ethane reacts with oxygen to produce carbon dioxide and water.
According to the balanced equation (2 \text{C}_2\text{H}_6 + 7 \text{O}_2 \rightarrow 4 \text{CO}_2 + 6 \text{H}_2\text{O}), 2 molecules of (\text{C}_2\text{H}_6) react with 7 molecules of (\text{O}_2). Therefore, 56 molecules of (\text{C}_2\text{H}_6) would react with ( \frac{7}{2} \times 56 = 196 ) molecules of (\text{O}_2).
There are 8 oxygen atoms in 4CO2 molecules. Each carbon dioxide molecule has 2 oxygen atoms, so 4 CO2 molecules would have a total of 8 oxygen atoms.
There are 3 atoms in one CO2. So there will be 12 atoms in 4CO2.
2ATP+6NADH2+2FADH2+4CO2 per glucose molecule
The balanced equation for this combustion reaction is 2C2H6 + 7O2 -> 4CO2 + 6H2O. This means that for every 2 molecules of C2H6, we need 7 molecules of O2 to produce 4 molecules of CO2 and 6 molecules of H2O.
The balanced equation for the complete oxidation of acetylene (C2H2) burning in air is: 2C2H2 + 5O2 -> 4CO2 + 2H2O. This equation shows that two molecules of acetylene react with five molecules of oxygen to produce four molecules of carbon dioxide and two molecules of water.
2C2H2(g) + 5O2(g) = 2H2O(g) + 4CO2(g) or, 2 Acetylene molecules + 5 Oxygen molecules = 2 water molecules + 4 Carbon dioxide molecules (+ energy)
The reaction is :- 2C2H6 + 7O2 ----------> 4CO2 + 6H2O When one mole ethane is combusted 7/2 moles of oxygen are used. When 3 moles of ethane are combusted 3 x 7/2 moles of oxygen used. No. of oxygen molecules consumed =6.022 x 1023 x7/2= 21.077 x 1023=2.107 x 1024 molecules.
4cO2??? I think you mean '4CO2. This is carbon dioxide. There are only two(2) elements in carbon dioxide, they are Carbon & Oxygen. However, in one (1) molecule of carbon dioxide there are three(3) atoms, they are 1 carbon and 2 oxygen ; designated by the 'CO2'. The prefix '4' indicates that there are 4 molecules of carbon dioxide. This means in 4CO2 there are 4 carbon toms and 8(4 x 2) oxygen atoms. The CO2 the atoms are chemically combined. However, the '4' indicates that the four molecules are not chemically combined with each other, but discrete particles. (molecules). NB . In atomic symbols a one letter symbol is always written as a capital letter 'C' (Carbon), not 'c' If an atomic symbol contains two letters e.g. iron (Fe) , then the first letter is always a capital letter and the second letter is always a small case letter.
During glycolysis, 2 NADH molecules are produced. During the citric acid cycle, 6 NADH molecules are produced. Therefore, a total of 8 NADH molecules are produced during the complete breakdown of one molecule of glucose.
In the reaction 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(l), the entropy decreases. This is because the reactants consist of gaseous molecules, which have higher entropy due to their greater freedom of movement, while the products include liquid water, which has lower entropy. Additionally, there is a reduction in the number of gas molecules from 7 (2 C2H2 + 5 O2) to 4 (4 CO2), further contributing to the decrease in disorder. Overall, the transition from gas to liquid and the reduction in the number of gas molecules results in a net decrease in entropy.
2C2H6 + 7O2 --> 4CO2 + 6H2O
The balanced equation for the complete combustion of ethyne (C2H2) is: 2C2H2 + 5O2 -> 4CO2 + 2H2O