The density of ethanol is 0.789 g/mL. So 19.6 mL of ethanol weighs 0.789 g/mL * 19.6 mL = 15.464 g. The molar mass of ethanol is 2*12.011 + 6*1.008 + 15.999 = 46.069 g/mol. So, in 15.464 grams, there are 15.464 g / 46.069 g/mol = 0.33567 moles In one mole, there are 6.022*1023 molecules, so we have: 0.33567 moles * 6.022*1023 molecules/mole= 2.0214*1023 molecules. Using correct significant digits, that gives: 2.02*1023 molecules (or particles).
There are (5.41 \times 10^{23}) molecules of (O_2) in 0.900 moles.
From one molecule of glucose (sugar) you can obtain two molecules of ethanol. Glucose's chemical composition is C6H12O6 Carbon dioxide (Co2) is lost in the fermentation process so we are left with 2C2H5OH or two ethanol molecules! Hope it helps!
If Earth's atmosphere contained twice as many molecules as it does today, the atmospheric pressure would also double. This is because pressure is directly related to the number of gas molecules in the atmosphere.
Yes, candle wax does dissolve in ethanol. Ethanol is a good solvent for many organic compounds, including wax. It can break down the wax molecules and create a solution when mixed together.
In a sample of chlorine gas, all molecules are diatomic composed of two chlorine atoms. This means there is only one type of molecule in the sample, with a molecular formula Cl2.
The answer is 1,357.10 ex.23 molecules.
1.24*10^22
1.814*1022
To calculate the number of molecules in a sample of dimethylmercury, you would first need to determine the number of moles in the sample using the molar mass of dimethylmercury. Then you can use Avogadro's number (6.022 x 10^23 molecules/mol) to calculate the number of molecules.
To determine the number of molecules in a sample, we need to know the molar mass of dimethylmercury (C2H6Hg). The molar mass of dimethylmercury is approximately 230.62 g/mol. Using this molar mass, we can calculate that there are approximately 2.23 x 10^22 molecules in a 7.85-g sample of dimethylmercury.
To determine the number of molecules in a sample, you need to know the molar mass of the compound. For dimethylmercury, the molar mass is approximately 230.6 g/mol. You can then use the formula n = m/M, where n is the number of moles, m is the mass of the sample, and M is the molar mass, to calculate the number of molecules in the sample.
To calculate the number of molecules in a 5.20-g sample of dimethylmercury, you first need to determine the molar mass of dimethylmercury (Me2Hg). Then, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert the mass to moles and then to molecules.
Mass of 1 liter ethanol = 800 gram Molar Mass of ethanol = 46.07 gram/mol Therefore, Number of moles in 1 liter ethanol = 800/46.07 = 17.365 mol Number of molecules in 1 mol of ethanol = 6.023 × 10²³ molecules Therefore, Number of molecules in 1 liter of ethanol = 17.365 × 6.023 × 10²³ molecules = 104.599 × 10²³ molecules = 1.05 × 10²⁵ molecules
To calculate the number of molecules in a sample, you need to know the molecular weight of the substance. The molecular weight of dimethylmercury is approximately 214.77 g/mol. Using this information, you can determine the number of moles in the 4.75-g sample and then convert that to the number of molecules using Avogadro's number.
To find the number of molecules in a 6.30g sample of dimethylmercury, you need to know the molar mass of dimethylmercury (the molecular formula is C2H6Hg) and Avogadro's number. First, calculate the number of moles in the sample by dividing the mass by the molar mass. Then, use Avogadro's number to convert moles to molecules by multiplying by 6.022 x 10^23.
To determine the number of molecules in a sample, you need to know the molar mass of the substance. The molar mass of dimethylmercury (CH3)2Hg is approximately 230.65 g/mol. Utilizing the formula: moles = mass/molar mass, and then using Avogadro's number (6.022 x 10^23 molecules/mol), you can calculate the number of molecules in the sample.
There are (5.41 \times 10^{23}) molecules of (O_2) in 0.900 moles.