Assuming you mean oxygen gas, the number of molecules can be found by first finding the number of moles = mass of oxygen (4g) / Molecular mass of oxygen gas (32 g mol-1)
This tells us there is 0.125 mol of oxygen gas present.
The number of molecules present is given by the number of moles x the avogadro constant (6.022x10^23)
So the number of oxygen gas molecules present is equal to 0.125 x 6.022x10^23 = 7.5275x10^22 molecules
1 mole O2 weighs 32 gso 64 g O2 is 2 mol O2 gaswhich has 2 X 6.022 X 1023 = 1.2066 X 1024 molecules of O2
To find the number of molecules in 25.0 g of NO2, you can start by converting the mass to moles using the molar mass of NO2. Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
Both nitrogen and oxygen exist at standard temperature and pressure as diatomic molecules. Therefore, the relative masses of equal numbers of molecules of the substance will the same as the ratios of their atomic masses, which are 15.9994 for oxygen and 14.0067 for nitrogen. The mass of oxygen that contains the same number of molecules as 42 g of nitrogen is 42(15.9994/14.0067) or 48 g, to the justified number of significant digits.
The ratio of mass of copper to oxygen in the sample is 4:1. This is determined by dividing the mass of copper (64 g) by the mass of oxygen (16 g).
The balanced chemical equation for the reaction between aluminum and oxygen is 4Al + 3O2 → 2Al2O3. Using the stoichiometry of the equation, you would need 50 g of aluminum to react with 75 g of oxygen, since the molar ratio between Al and O2 is 4:3.
There are 40 atoms of oxygen in five molecules of Penicillin G.
no. If it was, we would have oxygen balloons instead of helium balloons.
1 mole O2 weighs 32 gso 64 g O2 is 2 mol O2 gaswhich has 2 X 6.022 X 1023 = 1.2066 X 1024 molecules of O2
To find the number of oxygen molecules in the balloon, you can first calculate the number of moles of O2 using its molar mass (32 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, the balloon contains approximately 1.15 x 10^23 oxygen molecules.
The molar mass of water is 18 g/mol, so 29.2 g is equivalent to 1.62 mol of water. Through electrolysis, each water molecule decomposes into 1 molecule of oxygen and 2 molecules of hydrogen. Therefore, 1.62 mol of water will produce 1.62 mol of oxygen molecules, which is equivalent to 9.73 x 10^23 molecules of oxygen.
36 g water contain 32 g oxygen.32 g oxygen is equivalent to 1 mol oxygen.1 mol has 6,023.10e23 molecules (or atoms, ions).
To completely metabolize 180.0g of glucose, you would need to breathe in 540.0g of oxygen. This is based on the stoichiometry of cellular respiration, where one molecule of glucose reacts with six molecules of oxygen to produce carbon dioxide and water.
1) 7 g co 2)16 g so2 3)11 g co2
The needed mass of oxygen is 16 g.
That's correct: CH(4) + 2O(2) → CO(2) + 2H(2)O However, if there is not enough oxygen available, then 2 molecules of methane will react with 3 molecules of oxygen to produce 2 molecules of [poisonous] carbon monoxide and 2 molecules of water: 2CH(4) + 3O(2) → 2CO + 2H(2)O
2C2H2(g) + 5O2(g) = 2H2O(g) + 4CO2(g) or, 2 Acetylene molecules + 5 Oxygen molecules = 2 water molecules + 4 Carbon dioxide molecules (+ energy)
The number of oxygen atoms is 0,188.10e23.