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There are 3.79 times 6.02*1023 molecules in 3.79 mol CCl4 with 3.79 times 5 (=4+1) atoms in 3.79 mol CCl4

So multplying all this gives you the answer:

3.79 * 6.02*1023 * 5 = 114*1023 = 1.14*1025 atoms in 3.79 mole

(of any compound with 5 atoms in one molecule)

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